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我很难用 spring MVC 修复这个 406 错误。我想做的是进行 Ajax 调用并获得 json 响应。另外我正在尝试使用警报（js）输出该json。这就是我实现它的方式。

我的控制器：

    @RequestMapping(value="/search", headers="Accept=*/*", produces=MediaType.APPLICATION_JSON_VALUE) // no 'params' argument
    @ResponseBody
    public Customer findByFirstName() {
         Customer test = new Customer();
         test.setFirstName("test");
         return test;
     }

顾客：

    @Entity
    @Table(name="customer",catalog="revised_cws_db")
    public class Customer  implements java.io.Serializable {
        @Id @GeneratedValue(strategy=IDENTITY)
        @Column(name="id", unique=true, nullable=false)
        private int id;
        @Version @Temporal(TemporalType.TIMESTAMP)
        @Column(name="timestamp", nullable=false)
        private Date timestamp;
        @ManyToOne(fetch=FetchType.LAZY)
        @JoinColumn(name="address_id", nullable=false)
        private Address address;
        @Temporal(TemporalType.DATE)
        @Column(name="birth_date", nullable=false, length=10)
        private Date birthDate;
        @Column(name="first_name", nullable=false, length=45)
        private String firstName;
        @Column(name="middle_name", nullable=false, length=45)
        private String middleName;
       @Column(name="gender", nullable=false, length=45)
       private String gender;
       @Column(name="contact_number", length=45)
       private String contactNumber;
       @Column(name="family_members_count", nullable=false, length=45)
       private String familyMembersCount;
       @Column(name="occupation_id", nullable=false)
       private int occupationId;
       @Column(name="active", nullable=false)
       private boolean active;
       @OneToMany(fetch=FetchType.LAZY, mappedBy="customer")
       private Set<Issues> issueses = new HashSet<Issues>(0);
       @OneToMany(fetch=FetchType.LAZY, mappedBy="customer")
       private Set<Account> accounts = new HashSet<Account>(0);  
       public Customer() {
       }
       public Customer(int id, Address address, Date birthDate, String firstName, String middleName, String gender, String familyMembersCount, int occupationId, boolean active) {
            this.id = id;
            this.address = address;
            this.birthDate = birthDate;
            this.firstName = firstName;
            this.middleName = middleName;
            this.gender = gender;
            this.familyMembersCount = familyMembersCount;
            this.occupationId = occupationId;
            this.active = active;
       }
       public Customer(int id, Address address, Date birthDate, String firstName, String middleName, String gender, String contactNumber, String familyMembersCount, int occupationId, boolean active, Set<Issues> issueses, Set<Account> accounts) {
            this.id = id;
            this.address = address;
            this.birthDate = birthDate;
            this.firstName = firstName;
            this.middleName = middleName;
            this.gender = gender;
            this.contactNumber = contactNumber;
            this.familyMembersCount = familyMembersCount;
            this.occupationId = occupationId;
            this.active = active;
            this.issueses = issueses;
            this.accounts = accounts;
       }
       //getters, setters omitted

小服务程序：

    <bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>

<mvc:annotation-driven/>

<context:component-scan base-package="com.controller" />

<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
    <property name="cacheSeconds" value="0" />
</bean>
<!--
Most controllers will use the ControllerClassNameHandlerMapping above, but
for the index controller we are using ParameterizableViewController, so we must
define an explicit mapping for it.
-->
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
    <property name="mappings">
        <props>
            <prop key="index.htm">indexController</prop>
        </props>
    </property>
</bean>

<bean id="viewResolver"
      class="org.springframework.web.servlet.view.InternalResourceViewResolver"
      p:prefix="/WEB-INF/jsp/"
      p:suffix=".jsp" />

<!--
The index controller.
-->
<bean name="indexController"
      class="org.springframework.web.servlet.mvc.ParameterizableViewController"
      p:viewName="index" />

jsp：

    <%@taglib uri = "http://java.sun.com/jsp/jstl/core" prefix="c" %>
    <%@taglib uri="http://www.springframework.org/tags/form" prefix="form"%>
    <%@page contentType="text/html" pageEncoding="UTF-8"%>
    <!DOCTYPE html>
     <html>
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>JSP Page</title>
    <script type="text/javascript" src="http://code.jquery.com/jquery-1.10.1.min.js"></script>
    <script>
        $(document).ready(function() {
            $(".search-form").keyup(function() {
                if ($(this).val().length >= 2) {
                    $('#searchForm').submit();
                }
            });
            $('#searchForm').submit(function(event) {    
                $.ajax({
                    dataType: 'json',
                    data : $(this).serialize(),
                    url: $(this).attr("action"),
                    success: function( result ) {
                        alert("test");
                    }
                });
                event.preventDefault();
            });

        });
    </script>
</head>
<body>
    <h1>Customers</h1>
    <form  id="searchForm" action="search.htm">
        Search Customer:
        <input class="search-form" name="firstName" placeholder="First Name">
        <input type="submit">
    </form>
</body>

我已经添加了以下罐子：

  • 杰克逊核心 asl 1.9.13
  • 杰克逊映射器 asl 1.9.13
  • 杰克逊核心 2.4.4
  • 杰克逊数据绑定 2.4.4
  • 杰克逊注解 2.4.4

我不知道怎么了。我会很感激任何建议。

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