c - C: XNOR / 异或门？

Question

我试图找到用 C 语言编写 XNOR 门的最有效方法。

if(VAL1 XNOR VAL2)
{
    BLOCK;
}

有什么建议么？

谢谢。

Answer 1

With two operands this is quite simple:

if (val1 == val2)
{
    block;
}

Answer 2

if(!(val1^val2))
{
    block;
}

编辑：在逻辑运算之外，您可能想要~(val1^val2)准确，但我发现！更清晰。

Answer 3

Presuming val1 and val2 are to be treated in the normal C logical boolean fashion (non-zero is true), then:

if (!val1 ^ !!val2)
{

}

will do the trick.