#1111 - Invalid use of group function由于 IF 循环中嵌入了两个 SUM() 调用，以下查询失败并抱怨 。到目前为止，我正在尝试在迁移到另一个 SQL 查询时完成相同的目标，但我遇到了困难，有人能指出我正确的方向吗？
数据库由一个表组成，如果客户没有立即支付发票，而是通过分期付款invoices，可能会有一些表。invoices_payments知道这一点，我试图总结所有 invoices.invoice_total 减去每个 invoices_payments.payment_date 不等于当前周仅当 invoices.issued_date 等于当前周，如果不是，那么我试图总结所有 invoices_payments.payment_amount 其中 invoices_payments .payment_date 等于当前周。
SELECT
SUM(
IF (
YEARWEEK(i.issue_date, 1) = YEARWEEK(NOW(), 1),
i.invoice_total,
0
)
) AS week_invoiced,
##SUM Functions embedded inside the next IF are causing error: #1111 - Invalid use of group function
SUM(
IF (
## If payment is issued on current week
i.issued_date IS NOT NULL
AND YEARWEEK(i.issued_date, '%Y%m') = YEARWEEK(NOW(), '%Y%m'),
## Sum each invoice.invoice_total and substract each invoices_payments not issued on current week
SUM(i.invoice_total) - SUM(
IF (
ip.id IS NOT NULL
AND YEARWEEK(ip.payment_date, 1) != YEARWEEK(NOW(), 1),
ip.payment_amount,
0
)
),
IF (
## If payment is not issued on current week
i.issued_date IS NULL
OR (
i.issued_date IS NOT NULL
AND YEARWEEK(i.issued_date, '%Y%m') != YEARWEEK(NOW(), '%Y%m')
),
## Sum each invoices_payments issued on current week
SUM(
IF (
ip.id IS NOT NULL
AND YEARWEEK(ip.payment_date, 1) = YEARWEEK(NOW(), 1),
ip.payment_amount,
0
)
),
0
)
)
) AS week_paid,
SUM(
IF (
DATE_FORMAT(i.issue_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m'),
i.invoice_total,
0
)
) AS month_invoiced
FROM
`invoices` AS i
INNER JOIN `currency` AS cur ON i.currency_id = cur.id
LEFT JOIN `invoices_payments` AS ip ON ip.invoice_id = i.id
WHERE
i.coach_id = 279
AND (
DATE_FORMAT(i.issue_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
OR DATE_FORMAT(i.issued_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
OR (
ip.id IS NOT NULL
AND DATE_FORMAT(ip.payment_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
)
)
GROUP BY
i.id