javascript - ES5 - 从 src 路径解析脚本版本

Question

我希望有人已经完成了这项工作，但我想做的是输出各种 javascript 库的语义版本列表。假设我有以下输入：

• https://code.jquery.com/jquery-2.1.3.js
• //maxcdn.bootstrapcdn.com/bootstrap/3.3.4/css/bootstrap.min.css
• https://cdnjs.cloudflare.com/ajax/libs/1140/2.0/1140.css
• https://cdnjs.cloudflare.com/ajax/libs/Base64/0.3.0/base64.min.js
• https://cdnjs.cloudflare.com/ajax/libs/angular-google-maps/2.1.0-X.10/angular-google-maps.min.js
• https://cdnjs.cloudflare.com/ajax/libs/swagger-ui/2.1.8-M1/swagger-ui.min.js
• https://cdnjs.cloudflare.com/BLAH/BLAH.min.js

我想对这些字符串中的每一个调用一个函数，并让它从路径中输出 semver：

• 2.1.3
• 3.3.4
• 1140 或 2.0（首选）
• 0.3.0
• 2.1.0-X.10
• 2.1.8-M1
• 无效的

我无法找到任何现有的库，并希望有人能方便地使用 IE9ish。

Answer 1

通过使用以下代码，我能够使它工作：

  it('should parse version from script source', () => {
    function getVersion(source:string) {
      if (!source) {
        return null;
      }

      var versionRegex = /(v?((\d+)\.(\d+)(\.(\d+))?)(?:-([\dA-Za-z\-]+(?:\.[\dA-Za-z\-]+)*))?(?:\+([\dA-Za-z\-]+(?:\.[\dA-Za-z\-]+)*))?)/;
      var matches = versionRegex.exec(source);
      if (matches && matches.length > 0) {
        return matches[0];
      }

      return null;
    }

    expect(getVersion('https://code.jquery.com/jquery-2.1.3.js')).toBe('2.1.3');
    expect(getVersion('//maxcdn.bootstrapcdn.com/bootstrap/3.3.4/css/bootstrap.min.css')).toBe('3.3.4');
    expect(getVersion('https://cdnjs.cloudflare.com/ajax/libs/1140/2.0/1140.css')).toBe('2.0');
    expect(getVersion('https://cdnjs.cloudflare.com/ajax/libs/Base64/0.3.0/base64.min.js')).toBe('0.3.0');
    expect(getVersion('https://cdnjs.cloudflare.com/ajax/libs/angular-google-maps/2.1.0-X.10/angular-google-maps.min.js')).toBe('2.1.0-X.10');
    expect(getVersion('https://cdnjs.cloudflare.com/ajax/libs/swagger-ui/2.1.8-M1/swagger-ui.min.js')).toBe('2.1.8-M1');
    expect(getVersion('https://cdnjs.cloudflare.com/BLAH/BLAH.min.js')).toBe(null);
  });