4

我想通过索引获取可变参数模板中的类型。索引被指定为模板参数。我设法找到了一个有效的“黑客”，但我相信它不符合可变参数模板编程的精神。此外，它使用额外的内存。

这是带有一些解释的代码：

template <typename... InputPortTypes>
class PipelineReceiver
{

protected:

    // This tuple is used for storing types only
    // Hence, I would like to get rid of it, but I am not sure how.
    std::tuple<
    std::function<std::unique_ptr<InputPortTypes> (int)>...
    > InputPortsTuple;

    // This vector is used for storing the actual objects
    // This is needed to be able to access/change its elements
    // during run time later on.
    // The vector is used for storage of function pointers (i.e. of type std::function)
    // that represent methods of another object upstream the pipeline.
    std::vector<boost::any> InputPortsVector;

public:

    PipelineReceiver()
        {
            // create an empty vector of the required size
            InputPortsVector.resize(sizeof...(InputPortTypes));
        }

    void connectPorts(int InputPortIndex, boost::any c_OutputPort)
        {
            // connect ports
            InputPortsVector[InputPortIndex] = c_OutputPort;
        }

     // this function needs to be modified to avoid using InputPortsTuple
    template<int N>
    void getInputPortValue(void)
        {
            std::cout <<
                *boost::any_cast<decltype(std::get<N>(this -> InputPortsTuple))>(
                    InputPortsVector[N]
                    )(0) <<
                std::endl;
        }

};

我想删除该对象InputPortsTuple并将其替换为某种形式的递归过程，以推断getInputPortValue.

理想情况下，我想N成为一个动态参数而不是模板参数。但是，我不确定这是否可能。

4

1 回答 1

8

你可以简单地滥用std::tuple_element：

typename std::tuple_element<N, std::tuple<InputPortTypes...>>::type

注意：如果你可以使用 C++14，

std::tuple_element_t<N, std::tuple<InputPortTypes...>>

是做同样事情的更好方法。不过，并非所有常见的编译器都知道它。

于 2015-04-19T11:07:42.747 回答