40

When I open a file for reading in Haskell, I've found that I can't use the contents of the file after closing it. For example, this program will print the contents of a file:

main = do inFile <- openFile "foo" ReadMode
          contents <- hGetContents inFile
          putStr contents
          hClose inFile

I expected that interchanging the putStr line with the hClose line would have no effect, but this program prints nothing:

main = do inFile <- openFile "foo" ReadMode
          contents <- hGetContents inFile
          hClose inFile
          putStr contents

Why does this happen? I'm guessing it has something to do with lazy evaluation, but I thought these expressions would get sequenced so there wouldn't be a problem. How would you implement a function like readFile?

4

6 回答 6

39

As others have stated, it is because of lazy evaluation. The handle is half-closed after this operation, and will be closed automatically when all data is read. Both hGetContents and readFile are lazy in this way. In cases where you're having issues with handles being kept open, typically you just force the read. Here's the easy way:

import Control.Parallel.Strategies (rnf)
-- rnf means "reduce to normal form"
main = do inFile <- openFile "foo" 
          contents <- hGetContents inFile
          rnf contents `seq` hClose inFile -- force the whole file to be read, then close
          putStr contents

These days, however, nobody is using strings for file I/O anymore. The new way is to use Data.ByteString (available on hackage), and Data.ByteString.Lazy when you want lazy reads.

import qualified Data.ByteString as Str

main = do contents <- Str.readFile "foo"
          -- readFile is strict, so the the entire string is read here
          Str.putStr contents

ByteStrings are the way to go for big strings (like file contents). They are much faster and more memory efficient than String (= [Char]).

Notes:

I imported rnf from Control.Parallel.Strategies only for convenience. You could write something like it yourself pretty easily:

  forceList [] = ()
  forceList (x:xs) = forceList xs

This just forces a traversal of the spine (not the values) of the list, which would have the effect of reading the whole file.

Lazy I/O is becoming considered evil by experts; I recommend using strict bytestrings for most of file I/O for the time being. There are a few solutions in the oven which attempt to bring back composable incremental reads, the most promising of which is called "Iteratee" by Oleg.

于 2008-11-18T02:00:22.963 回答
4

[Update: Prelude.readFile causes problems as described below, but switching over to using Data.ByteString's versions of everything works: I no longer get the exception.]

Haskell newbie here, but currently I don't buy the claim that "readFile is strict, and closes the file when it's done":

go fname = do
   putStrLn "reading"
   body <- readFile fname
   let body' = "foo" ++ body ++ "bar"
   putStrLn body' -- comment this out to get a runtime exception.
   putStrLn "writing"
   writeFile fname body'
   return ()

That works as it stands on the file that I was testing with, but if you comment out the putStrLn then apparently the writeFile fails. (Interesting how lame Haskell exception messages are, lacking line numbers etc.?)

Test> go "Foo.hs"
reading
writing
Exception: Foo.hs: openFile: permission denied (Permission denied)
Test> 

?!?!?

于 2008-11-19T01:16:34.753 回答
2

This is because hGetContents doesn't do anything yet: it's lazy I/O. Only when you use the result string the file is actually read (or the part of it that is needed). If you want to force it to be read, you can compute its length, and use the seq function to force the length to be evaluated. Lazy I/O can be cool, but it can also be confusing.

For more information, see the part about lazy I/O in Real World Haskell, for example.

于 2008-11-17T22:58:06.077 回答
1

As previously noted, hGetContents is lazy. readFile is strict, and closes the file when it's done:

main = do contents <- readFile "foo"
          putStr contents

yields the following in Hugs

> main
blahblahblah

where foo is

blahblahblah

Interestingly, seq will only guarantee that some portion of the input is read, not all of it:

main = do inFile <- openFile "foo" ReadMode
          contents <- hGetContents $! inFile
          contents `seq` hClose inFile
          putStr contents

yields

> main
b

A good resource is: Making Haskell programs faster and smaller: hGetContents, hClose, readFile

于 2008-11-17T23:55:05.777 回答
1

If you want to keep your IO lazy, but to do it safely so that errors such as this don't occur, use a package designed for this such as safe-lazy-io. (However, safe-lazy-io doesn't support bytestring I/O.)

于 2010-11-03T10:42:17.753 回答
0

The explanation is rather long to be included here. Forgive me for dispensing a short tip only: you need to read about "semi-closed file handles" and "unsafePerformIO".

In short - this behaviour is a design compromise between a semantic clearness and lazy evaluation. You should either postpone hClose until you are absolutely sure you woudnt be doing anything with the file content (like, call it in error handler, or somesuch), or use something else besides hGetContents to get file contents non-lazily.

于 2008-11-17T20:52:42.103 回答