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另一个问题,Accessing Keys from Linux Input Device

提供了有关如何在没有按下其他键时在 Linux 文本控制台中识别修饰键按下的工作 C 代码。

但是,要应用该技巧,您必须知道/dev/input/event*记录键盘事件的特定文件。

如何确定该文件的名称?

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2 回答 2

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我更喜欢下一个解决方案,因为它在内部解析设备文件。
如果我们检查 /proc/bus/input/devices 的内容,我们会发现如下内容:

# cat /proc/bus/input/devices
I: Bus=0019 Vendor=0002 Product=0001 Version=0100
N: Name="vmouse"
P: Phys=vmouse/input0
S: Sysfs=/devices/virtual/input/input0
U: Uniq=
H: Handlers=mouse0 event0
B: PROP=0
B: EV=7
B: KEY=70400 0 0 0 0 0 0 0 0
B: REL=143

I: Bus=0019 Vendor=0001 Product=0001 Version=0100
N: Name="sunxi-ths"
P: Phys=sunxiths/input0
S: Sysfs=/devices/virtual/input/input3
U: Uniq=
H: Handlers=event3
B: PROP=0
B: EV=9
B: ABS=100 0

I: Bus=0003 Vendor=1220 Product=0008 Version=0100
N: Name="HID 1220:0008"
P: Phys=usb-sunxi-ohci-1/input0
S: Sysfs=/devices/platform/sunxi-ohci.3/usb7/7-1/7-1:1.0/input/input6
U: Uniq=
H: Handlers=sysrq kbd event1
B: PROP=0
B: EV=120013
B: KEY=10000 7 ff9f207a c14057ff febeffdf ffefffff ffffffff fffffffe
B: MSC=10
B: LED=1f

I: Bus=0003 Vendor=1220 Product=0008 Version=0100
N: Name="HID 1220:0008"
P: Phys=usb-sunxi-ohci-1/input1
S: Sysfs=/devices/platform/sunxi-ohci.3/usb7/7-1/7-1:1.1/input/input7
U: Uniq=
H: Handlers=kbd mouse1 event2
B: PROP=0
B: EV=1f
B: KEY=4837fff 72ff32d bf544446 0 0 1f0001 20f90 8b17c000 677bfa d941dfed 9ed680 4400 0 10000002
B: REL=143
B: ABS=1 0
B: MSC=10

所以我们唯一需要的是在出现“EV=120013”字符串的块中找到事件设备号:

#include <fcntl.h>
#include <stdio.h>
#include <string>
#include <string.h>
#include <unistd.h>

using namespace std;

string getInputDeviceName() {
    int rd;
    std::string devName;
    const char* pdevsName = "/proc/bus/input/devices";

    int devsFile = open(pdevsName, O_RDONLY);
    if (devsFile == -1) {
        printf("[ERR] Open input devices file: '%s' is FAILED\n", pdevsName);
    }
    else {
        char devs[2048];

        if ((rd = read(devsFile, devs, sizeof(devs) - 1)) < 6) {
            printf("[ERR] Wrong size was read from devs file\n");
        }
        else {
            devs[rd] = 0;

            char *pHandlers, *pEV = devs;
            do {
                pHandlers = strstr(pEV, "Handlers=");
                pEV = strstr(pHandlers, "EV=");
            }
            while (pHandlers && pEV && 0 != strncmp(pEV + 3, "120013", 6));

            if (pHandlers && pEV) {
                char* pevent = strstr(pHandlers, "event");
                if (pevent) {
                    devName = string("/dev/input/event");
                    devName.push_back(pevent[5]);
                }
                else {
                    printf("[ERR] Abnormal keyboard event device\n");
                }
            }
            else {
                printf("[ERR] Keyboard event device not found\n");
            }
        }
    }

    return devName;
}

注意1:此代码适用于编号小于 10 的事件设备。注意 2:请检查“
devs ”缓冲区大小,在您的系统上 2048 字节可能不够。

于 2017-01-24T10:43:46.317 回答
0

我有这个完全相同的问题。这是我的解决方案:

#include <iostream>
#include <string>
#include <stdio.h>

static const std::string COMMAND_GET_INPUT_DEVICE_EVENT_NUMBER =
    "grep -E 'Handlers|EV=' /proc/bus/input/devices |"
    "grep -B1 'EV=120013' |"
    "grep -Eo 'event[0-9]+' |"
    "grep -Eo '[0-9]+' |"
    "tr -d '\n'";

std::string executeCommand(const char *cmd) {
  FILE *pipe = popen(cmd, "r");
  char buffer[128];
  std::string result = "";
  while (!feof(pipe))
    if (fgets(buffer, 128, pipe) != NULL)
      result += buffer;
  pclose(pipe);
  return result;
}

std::string getInputDevicePath() {
  return "/dev/input/event" +
         executeCommand(COMMAND_GET_INPUT_DEVICE_EVENT_NUMBER.c_str());
}

int main() {
  std::cout << getInputDevicePath() << std::endl;
  return 0;
}
于 2015-05-23T11:49:18.060 回答