0

这个查询给了我想要的结果，但我不能每次都运行这个查询。这 2 个循环让我付出了代价。所以我需要实现类似视图的东西。但是逻辑涉及临时表，视图中也不允许这样做.so，是否有任何其他方式来存储此结果或更改查询，以减少我的成本。

DECLARE @Temp TABLE (
    [SiteID] VARCHAR(100)
    ,[StructureID] INT
    ,[row] DECIMAL(4, 2)
    ,[col] DECIMAL(4, 2)
    )
DECLARE @siteID VARCHAR(100)
    ,@structureID INT
    ,@struct_row INT
    ,@struct_col INT
    ,@rows_count INT
    ,@cols_count INT
    ,@row INT
    ,@col INT

DECLARE structure_cursor CURSOR
FOR
SELECT StructureID
    ,SiteID
    ,Cols / 8.5 AS Cols
    ,Rows / 11 AS Rows
FROM Structure
WHERE SellerID = 658 --AND StructureID = 55

OPEN structure_cursor

FETCH NEXT
FROM structure_cursor
INTO @structureID
    ,@siteID
    ,@struct_col
    ,@struct_row

SELECT @rows_count = 1
    ,@cols_count = 1
    ,@row = 1
    ,@col = 1

WHILE @@FETCH_STATUS = 0
BEGIN
    WHILE @row <= @struct_row
    BEGIN
        WHILE @col <= @struct_col
        BEGIN
            --PRINT 'MEssage';
            INSERT INTO @Temp (
                SiteID
                ,StructureID
                ,row
                ,col
                )
            VALUES (
                @siteID
                ,@structureID
                ,@rows_count
                ,@cols_count
                )

            SET @cols_count = @cols_count + 1;
            SET @col = @col + 1;
        END

        SET @cols_count = 1;
        SET @col = 1;
        SET @rows_count = @rows_count + 1;
        SET @row = @row + 1;
    END

    SET @row = 1;
    SET @col = 1;
    SET @rows_count = 1;

    FETCH NEXT
    FROM structure_cursor
    INTO @structureID
        ,@siteID
        ,@struct_col
        ,@struct_row
END

CLOSE structure_cursor;

DEALLOCATE structure_cursor;

SELECT * FROM @Temp

图 1 图 2

4

3 回答 3

2

使用基于集合的操作执行此操作。我想你只是想要insert . . . select：

INSERT INTO @Temp (SiteID, StructureID, row, col)
    SELECT StructureID, SiteID, Cols / 8.5 AS Cols, Rows / 11 AS Rows
    FROM Structure
    WHERE SellerID = 658;

您应该避免使用游标，除非您出于某种原因确实需要它们（例如调用存储过程或在每一行上使用动态 SQL）。

编辑：

阅读逻辑，您似乎想根据每行的限制插入行。您仍然不想使用光标。为此，您需要一个数字生成器master..spt_values，如果它有足够的行，它是一个方便的生成器。所以：

with n as (
      select row_number() over (order by (select null)) as n
      from master..spt_values
     ) 
INSERT INTO @Temp (SiteID, StructureID, row, col)
    SELECT StructureID, SiteID, ncol.n / 8.5 AS Cols, nrow.n / 11 AS Rows
    FROM Structure s JOIN
         n ncol
         ON ncol.n <= s.struct_col CROSS JOIN
         n nrow
         ON nrow <= s.struct_row
    WHERE SellerID = 658;
于 2015-04-15T11:46:43.977 回答
1

您可以生成行数和列数，然后与它们交叉应用，如下所示。我遗漏了您的 SellerID 条件。

;WITH Cols
AS
(
    SELECT StructureID, SiteID, CAST(Cols / 8.5 AS INT) AS Col
    FROM Structure
    UNION ALL
    SELECT s.StructureID, s.SiteID, Col - 1
    FROM Structure s
        INNER JOIN Cols c ON s.StructureID = c.StructureID AND s.SiteID = c.SiteID
    WHERE Col > 1
)
, Rows
AS
(
    SELECT StructureID, SiteID, CAST(Rows / 11 AS INT) AS Row
    FROM Structure
    UNION ALL
    SELECT s.StructureID, s.SiteID, Row - 1
    FROM Structure s
        INNER JOIN Rows r ON s.StructureID = r.StructureID AND s.SiteID = r.SiteID
    WHERE Row > 1
)
--INSERT INTO @Temp (SiteID, StructureID, row, col)
SELECT s.SiteID, s.StructureID, r.Row, c.Col 
FROM Structure s
    CROSS APPLY Cols c
    CROSS APPLY Rows r
WHERE s.StructureID = c.StructureID AND s.SiteID = c.SiteID
    AND s.StructureID = r.StructureID AND s.SiteID = r.SiteID
于 2015-04-15T12:18:41.370 回答
0

我们可以通过使用CROSS APPLYand来做到这一点CTE。

CREATE TABLE Structure(SiteID varchar(20), StructureID int, 
Cols decimal(18,2), [Rows] decimal(18,2))

INSERT INTO Structure (SiteID, StructureID, Cols, [Rows])

VALUES

('MN353970', 51,17,22),
('MN272252', 52,17,11)


;WITH RowCTE([Rows]) AS
(
    SELECT 1 
    UNION ALL
    SELECT 2
),
ColCTE(Cols) AS
(
    SELECT 1
    UNION ALL
    SELECT 2
)

SELECT SiteID, StructureID, R.Rows, C.Cols
FROM Structure s
CROSS APPLY
    (
        SELECT Cols FROM ColCTE
    ) C
CROSS APPLY
    (
        SELECT [Rows] FROM RowCTE
    ) R

Sql 小提琴演示

于 2015-04-15T12:41:46.857 回答