oracle9i - 如何在 SQL (Oracle) 中加入两个查询

Question

我怎样才能加入这些查询？

SELECT RCTDT, SUM(RCTAMOUNT), COUNT(RCTAMOUNT) FROM RECEIPTS4
WHERE RCTDT BETWEEN '01-nov-2009' AND '30-nov-2009' 
AND RCTTYPE='CA' AND RCTAMOUNT>0
GROUP BY RCTDT

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SELECT RCTDT, SUM(RCTAMOUNT), COUNT(RCTAMOUNT) FROM RECEIPTS4
WHERE RCTDT BETWEEN '01-nov-2009' AND '30-nov-2009' 
AND RCTTYPE='CQ' AND RCTAMOUNT>0
GROUP BY RCTDT

Answer 1

也许你的意思是这个

SELECT RCTDT,
 SUM(case when rcttype='CA' then RCTAMOUNT else null end) as CASUM, 
 COUNT(case when rcttype='CA' then RCTAMOUNT else null end) as CACOUNT,
 SUM(case when rcttype='CQ' then RCTAMOUNT else null end) as CQSUM, 
 COUNT(case when rcttype='CQ' then RCTAMOUNT else null end) as CQCOUNT,
FROM RECEIPTS4
WHERE RCTDT BETWEEN '01-nov-2009' AND '30-nov-2009' 
AND RCTTYPE in('CA','CQ') AND RCTAMOUNT>0
GROUP BY RCTDT

Answer 2

使用IN运算符：

SELECT RCTDT, SUM(RCTAMOUNT), COUNT(RCTAMOUNT) FROM RECEIPTS4
WHERE RCTDT BETWEEN '01-nov-2009' AND '30-nov-2009' 
AND RCTTYPE IN ('CA','CQ') AND RCTAMOUNT>0
GROUP BY RCTDT

Answer 3

SELECT RCTDT, SUM(RCTAMOUNT), COUNT(RCTAMOUNT) FROM RECEIPTS4 WHERE RCTDT BETWEEN '01-nov-2009' and '30-nov-2009' and RCTTYPE IN ('CA','CQ') AND RCTAMOUNT>0 GROUP BY RCTDT

也很有用。

Answer 4

在这个特定的例子中，使用INcletus 建议的。在其他情况下，如果无法从同一个 select 生成两个结果集，请使用 aUNION组合结果：

SELECT something FROM somewhere
UNION
SELECT something FROM somewhere_else