php - 可捕获的致命错误：类的对象无法转换为字符串

Question

UrunController.php

public function kontrolAction(){
    $kk = new urunler();
    $kk->kodkontrol($this->request->getPost());
    echo $kk;
}

---

urunler.php

public function kodkontrol(){
        while(1){
            $UrunKodu = chr(rand(65,90)).chr(rand(65,90)).'-'.rand(1,9999);
            $UKKontrol = $this->findFirst("urunBarkod = '{$UrunKodu}'");
            if($UKKontrol > 0){
                continue;
            } else{
                break;
            }
        }

        echo $UrunKodu;
}

Answer 1

实际上，我认为一个方法永远不应该echo什么。更好的方法是return做某事。但无论如何，如果你想回显一个对象，你应该看看__toString()方法。