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我使用 ; 构建并运行以下最小示例（无外部依赖项 C->Haskell Compiler, version 0.25.2 Snowboundest, 31 Oct 2014 build platform is "x86_64-darwin" <1, True, True, 1>）构建命令：

c2hs Structs.chs
ghci Structs.hs

但链接器抱怨

During interactive linking, GHCi couldn't find the following symbol: get_foo

问：为什么会这样，我该如何解决？提前谢谢

A : tl; dr : 我没有将 .c 编译成 .o 目标代码，呵呵！

代码如下：

结构体.chs

module Main where

import Foreign
import Foreign.C

#include "Structs.h"

{#pointer *foo as Foo#}

{#fun get_foo {`Int'} -> `Foo' return* #}

main :: IO ()
main = do
  foo <- get_foo 3
  a1 <- {#get struct foo->a#} foo
  print a1

结构体.h

struct foo {
  int a;
};

struct foo *get_foo(int n);

结构体.c

#include "Structs.h"

struct foo f;

struct foo *get_foo(int n)
{
  f.a = n;
  return &f;
}

结构体.hs

-- -- C2HS generated Hs file, edited for clarity
module Main where

import Foreign
import Foreign.C

type Foo = Ptr ()

get_foo :: Int -> IO Foo
get_foo p =
  get_foo'_ (fromIntegral p)

main :: IO ()
main = do
  foo <- get_foo 3
  a1 <- (\ptr -> peekByteOff ptr 0 :: IO CInt) foo
  print a1

foreign import ccall safe "Structs.chs.h get_foo"
  get_foo'_ :: CInt -> IO Foo

编辑：ghc --make Structs.hs给出相同的链接器错误：

$ ghc --make Structs.hs
Linking Structs1a ...
Undefined symbols for architecture x86_64:
"_get_foo", referenced from:
    _c2MX_info in Structs.o
    _c2Or_info in Structs.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
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1 回答 1

5

get_fooC 函数在 中定义，Structs.c因此您需要将其提供给 GHC。这应该有效：

gcc -o Structs_c.o -c Structs.c
ghc --make Structs.hs Structs_c.o

对于 GHCi，我认为您可以只说ghci Structs.hs Structs_c.o. 但是你肯定需要 C 目标文件！

于 2015-04-09T07:50:07.883 回答