1

我正在使用这种方法从 url 获取图像并且我正在下载多个图像下面称为“名称”的变量是图像名称的数组。我希望能够存储名称在数组中的所有图像为什么我保留这样的网址。它似乎运作良好，但我在选择一张图片或它们时遇到问题。

这是保存图像的代码

 String fileName="code";

                          try {
                                URL url = new URL("http://10.0.2.2/picure/"+name+".jpg");
                                HttpURLConnection conn = (HttpURLConnection) url.openConnection();
                                conn.setDoInput(true);
                                conn.connect();
                                InputStream is = conn.getInputStream();
                                Bitmap bm = BitmapFactory.decodeStream(is);
                                FileOutputStream fos = getActivity().openFileOutput(fileName, Context.MODE_PRIVATE);

                                ByteArrayOutputStream outstream = new ByteArrayOutputStream();

                                bm.compress(Bitmap.CompressFormat.JPEG, 100, outstream);
                                byte[] byteArray = outstream.toByteArray();

                                fos.write(byteArray);
                                fos.close();
                                Toast.makeText(getActivity()," connected", Toast.LENGTH_LONG).show();
                            } catch(Exception e) {



            }

这是收集图像的代码

字符串路径 = mContext.getFilesDir().toString(); 字符串文件名 = "代码";

    if (fileName != null && !fileName.equals("")) {
        Bitmap bMap = BitmapFactory.decodeFile(path + "/" + fileName);
        if (bMap != null) {
             category_logo.setImageBitmap(bMap);
        }
    }

我知道我保存的图像的名称，所以我如何专门选择那个

4

2 回答 2

1

使用 Asynctask 获取所有图像，此代码可以下载应用程序缓存目录中的图像：

class ImageDownloader extends AsyncTask<String, Void, File> {

            String imageurl;
            String name;
Context ctx;

            public ImageDownloader(Context context, String url, String fileName) {

                this.imageurl = url;
                this.name = fileName;
this.ctx = context;


            }
            @Override
            protected File doInBackground(String... urls) {

                    Bitmap mIcon;

                    File cacheDir = ctx.getCacheDir();
                    File f = new File(cacheDir, name);

                    try {
                        InputStream in = new java.net.URL(imageurl).openStream();
                        mIcon = BitmapFactory.decodeStream(in);

                        try {
                            FileOutputStream out = new FileOutputStream(
                                    f);
                            mIcon.compress(
                                    Bitmap.CompressFormat.JPEG,
                                    100, out);
                            out.flush();
                            out.close();
                            return f;

                        } catch (FileNotFoundException e) {

                            return null;
                        } catch (IOException e) {

                            return null;
                        }

                    } catch (Exception e) {

                        return null;
                    }


            }
            @Override
            protected void onPostExecute(File result) {

                super.onPostExecute(result);
                                                Toast.makeText(ctx," connected " + name, Toast.LENGTH_LONG).show();

            }


        }
    }

要调用 asynctask，您需要使用 FOR 来获取图像的所有名称和 url：

new ImageDownloader(getBaseContext(),url[i],name[i]).execute();

您可以使用您的代码编辑 doInBackground，但您使用的 HTTPConnection 在 API 22 中已弃用，请使用上面的示例，您可以更改目录。

对不起代码，您可以稍后重新格式化。

于 2015-04-07T20:57:59.463 回答
1 
@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == CODE_MULTIPLE_IMG_GALLERY && resultCode==RESULT_OK){
        ClipData clipData = data.getClipData();
        if (clipData!=null){
            File folderPath = new File(getIntent().getStringExtra("folderpath"));
            for (int i = 0;i< clipData.getItemCount();i++){
                ClipData.Item item = clipData.getItemAt(i);
                Uri uri = item.getUri();
                Bitmap selectedImage = loadFromUri(uri);
                File imagePath = new File(folderPath,System.currentTimeMillis()+".jpg");
                try {
                    outputStream = new FileOutputStream(imagePath);
                } catch (FileNotFoundException e) {
                    e.printStackTrace();
                }
                selectedImage.compress(Bitmap.CompressFormat.JPEG,100,outputStream);
                Log.d("uri",uri.toString());
                imageModelList.add(new ImageModel(uri.toString()));
            }
            imagesAdapter.notifyDataSetChanged();
            Toast.makeText(ImageDetailActivity.this, "Added Successfully!", Toast.LENGTH_SHORT).show();
        }
    }
}
public Bitmap loadFromUri(Uri photoUri) {
    Bitmap image = null;
    try {
        // check version of Android on device
        if(Build.VERSION.SDK_INT > 27){
            // on newer versions of Android, use the new decodeBitmap method
            ImageDecoder.Source source = ImageDecoder.createSource(this.getContentResolver(), photoUri);
            image = ImageDecoder.decodeBitmap(source);
        } else {
            // support older versions of Android by using getBitmap
            image = MediaStore.Images.Media.getBitmap(this.getContentResolver(), photoUri);
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
    return image;
}
于 2020-07-18T04:00:46.750 回答