2

我有一个带有两个参考字段（发送者和接收者）的猫鼬模式（约会）。两者都引用相同的架构（用户）。我正在尝试使用 mongoose-paginate 插件填充这两个字段。

约会架构片段。

var paginate = require('mongoose-paginate');

var AppointmentSchema = new Schema({
  dateCreated: {type: Date, default: Date.now},
  sender: {type: ObjectId, ref: 'User'},
  receiver: {type: ObjectId, ref: 'User'},
  message: String,
  
  .........................
  
AppointmentSchema.plugin(paginate);

var Appointment = mongoose.model('Appointment', AppointmentSchema);
module.exports = Appointment;

用户架构片段。

var UserSchema = new Schema({
  username: String,
  name: {
    first: String,
    middle: String,
    last: String
  },
  
  ..................
  
var User = mongoose.model('User', UserSchema);

module.exports = User;

猫鼬分页查询。

Appointment.paginate({}, request.query.page, request.query.limit,
    function(error, pageCount, appointments, itemCount) {
      if (error) {
         return console.log('ERRRRRRRRRR'.red);
      } else {
        console.log(appointments);
        return response.render('message/inbox',
        {
          pageTitle: "Trash",
          messages: appointments,
          pageCount: pageCount,
          itemCount: itemCount,
          currentPage: currentPage
        });
      }
    }, {columns: {}, populate: 'receiver', populate: 'sender', sortBy: {title: -1}});

这工作正常，但我想填充发送者和接收者字段。请问我该怎么做。我尝试以 JSON 格式传递字段，但没有成功。

4

2 回答 2

7

我只是传递了一系列字段来填充，它就像一个魅力。

Appointment.paginate({}, request.query.page, request.query.limit,
    function(error, pageCount, appointments, itemCount) {
      if (error) {
         return console.log('ERRRRRRRRRR'.red);
      } else {
        console.log(appointments);
        return response.render('message/inbox',
        {
          pageTitle: "Trash",
          messages: appointments,
          pageCount: pageCount,
          itemCount: itemCount,
          currentPage: currentPage
        });
      }
    }, {columns: {}, populate: ['receiver', 'sender'], sortBy: {title: -1}});
于 2015-04-04T22:17:21.133 回答
0

对于使用 mongoose-paginate-v2 的开发人员，您可以在分页选项中传递一个数组对象来填充多个引用。

Collection.paginate(query,{
   page : 1,
   limit : 10,
   populate : [
     {
       path : 'refName1',
       select : {field : 1}
     },
     {
       path : 'refName2',
       select : {field : 1}
     }
   ]
})
于 2022-02-10T10:16:38.587 回答