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我需要用 Serpent 和 Twofish 加密一组无符号字符(16 字节长)。我使用官方网站上的两个库-write in c-。我尝试使用它们,但我将获得的密文不正确。为了检查我使用这个网站。我不明白错误在哪里。
我的代码是:

keyInstance keyTwofish;
cipherInstance cipherTwofish;
unsigned char *buffer_out_twofish;

char path_file_twofish[DIM];
...
//Twofish
if(cipherInit(&cipherTwofish,MODE_ECB,NULL)!=TRUE)
{
   perror("[ERROR] Function module02: makeKey.\n");
   return 0;
}
//key_dim*8=128 and key is an unsigned char key [16] that contain key
makeKey(&keyTwofish, DIR_ENCRYPT, key_dim*8, key);
…
//Buffer in is unsigned char buffer_in[16] contain plaintext
//byte_for_file=16 than byte_for_file*8=128
//Buffer out is unsigned char buffer_out_twofish[16]
blockEncrypt(&cipherTwofish, &keyTwofish, buffer_in, byte_for_file*8, buffer_out_twofish);

对于 Serpent 是相同的实现。

当我打印变量类型的 sizeof 时,结果是:

Size of Char: 1
Size of Integer: 4
Size of Long: 8

当我这样做时:

printf("\nPrint Char Array: ");
for (int j = 0; j < byte_for_file; ++j)
   printf("%x ", buffer_in[j]);
printf("\nPrint long Array: ");
test(buffer_in, byte_for_file);

在哪里

void test (unsigned long * a, int b)
{
   for (int i = 0; i < b/sizeof(long); ++i)
      printf("%lx ", a[i]);
}

我明白了:

Print Char Array: 87 ae bd 58 71 75 1d 36 43 ab 1d ef 69 f5 54 d7 
Print long Array: 361d757158bdae87 d754f569ef1dab43 
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1 回答 1

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您使用的实现需要一个密钥作为 keyLen/4 ASCII 字符,表示密钥的十六进制值。

所以你应该改变这一行:

makeKey(&keyTwofish, DIR_ENCRYPT, key_dim*8, key);

进入

makeKey(&keyTwofish, DIR_ENCRYPT, strlen(key)*4, key);

因为十六进制值例如。0x30313233343536373839 不会被解释为 0123456789 而是 0x0300030103020303030403050306030703080309 和密钥 0123456789 将被解释为 0x00010203040506070809。

于 2015-04-17T18:25:33.830 回答