我想创建一个算法,但不知道如何开始。
这个算法实际上是一个方法,它接受一个包含 N 个对象的数组,其中包含一些属性 createdAt 和 value。我将数组从旧的到新的(createdAt)排序,然后我必须找出可用数据的一致性,这意味着每一个小时我至少有 5 条记录,每半小时有 2 条记录。
示例测试代码:
- (void) normalizeData:(NSArray*)records
{
// sort the records
NSArray* sortedRecords = [records sortWithCreatedAt];
// split all dates in the records, distinct them, and create a dictionary with a key for every date, for value create another dictionary with the hour as key and the records as the value.
NSArray* distinctDates = [sortedRecords valueForKeyPath:@"@distinctUnionOfObjects.createdAt"]; // should only consider month-day-year-hour
NSMutableDictionary* dictionary = [NSMutableDictionary dictionary];
for (NSDate* date in distinctDates)
{
NSString* stringDate = [date string];
NSArray* recordsForDate = [sortedRecords valueForKeyPath:[NSString stringWithFormat:@"[collect].{createdAt=%@}.self", stringDate]]; // let's say you got them with this line
[dictionary setObject:recordsForDate forKey:date];
}
for (NSDate* keyDate in dictionary)
{
NSArray* records = [dictionary objectForKey:keyDate];
Record* previousRecord = nil;
for (Records* record in records)
{
// I'll have to keep the previous record and compare the time difference with the new
NSInteger secondsAfterDate = 0;
if (previousRecord)
{
secondsAfterDate = [record.createdAt timeIntervalSinceDate:previousRecord.createdAt];
// add logic to create trend difference in a model that has for every hour of the records count, the records and suffice description
// logic if the records count and timespan is suffice.
}
previousRecord = record;
}
}
}
我将不胜感激对方法中的过程的任何贡献。
此外,最终目标是为处理的记录的每个结果创建一个返回(调用块处理程序)。逻辑应该以每小时至少 5 条记录以及它们之间的时间跨度在 15 分钟以内结束。