scala - 在Scalaz中实现“延迟”列表流的好方法是什么

Question

我试过这样做，但没有奏效：

Process("Hello", "Salut", "Bye", "Ciao").interleave(time.sleep(0.5.seconds).repeat)

Answer 1

(Process("Hello", "Salut", "Bye", "Ciao") zip (time.awakeEvery(0.5 s)) .map(_._1)