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首先是一些上下文：四个 MPR121 分线板 ( https://www.sparkfun.com/products/9695 ) 通过 i2C 连接到 Raspberry Pi 2。python 脚本从四个板上读取数据并将其发送到纯数据用 pd 发送。

目前，我已经设法获得了在终端上打印所需的所有数据。但是，我不确定如何在纯数据中获得相同的信息，因为我只收到短信（类似于“print: .join(map(str print: diff3))”）

我很确定我需要更改 os.system 行以适应变量，但我找不到如何做到这一点。

非常感谢您提前。

def send2Pd (message=' '):
os.system("echo '" + message + "' | pdsend 3000");

while True:

diff1 = [cap1.baseline_data(i)-cap1.filtered_data(i) for i in range(12)]
print 'Diff1:', '\t'.join(map(str, diff1))
send2Pd ('.join(map(str, diff1));')

diff2 = [cap2.baseline_data(i)-cap2.filtered_data(i) for i in range(12)]
print 'Diff2:', '\t'.join(map(str, diff2))
send2Pd ('.join(map(str, diff2));')

diff3 = [cap3.baseline_data(i)-cap3.filtered_data(i) for i in range(12)]
send2Pd ('.join(map(str, diff3));')
print 'Diff3:', '\t'.join(map(str, diff3))

diff4 = [cap4.baseline_data(i)-cap4.filtered_data(i) for i in range(12)]
print 'Diff4:', '\t'.join(map(str, diff4))
send2Pd ('.join(map(str, diff4));')

time.sleep(0.1)
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2 回答 2

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如果我理解正确，您只需要从传递给 send2Pd 的参数中删除引号，类似的send2Pd('\t'.join(map(str, diff1)))工作吗？

于 2015-03-30T14:33:15.030 回答
0

好的排序。

这段代码为纯数据中的每个上限提供了一行。

但是，它看起来确实非常耗资源（使用情况监视器标记为 50% 左右）并且没有运行 pd 补丁。有没有一种简单的方法可以提高效率？

谢谢！

import os
import sys
import time
import captouch as MPR121

# Create MPR121 instances
cap1 = MPR121.MPR121()
cap2 = MPR121.MPR121()
cap3 = MPR121.MPR121()
cap4 = MPR121.MPR121()

# Initialize communication with all 4 MPR121s
cap1.begin( 0x5a )
cap2.begin( 0x5b )
cap3.begin( 0x5d )
cap4.begin( 0x5c )

# Define send2Pd function
def send2Pd (message=' '):
    os.system("echo '" + message + "' | pdsend 3000");

# Start loop
while True:

    # Filtered and baseline data are commented out
    # filtered = [cap1.filtered_data(i) for i in range(12)]
    # print 'Filt:', '\t'.join(map(str, filtered))
    # base = [cap1.baseline_data(i) for i in range(12)]
    # print 'Base:', '\t'.join(map(str, base))

    # Difference for all 4 boards are calculated, printed in terminal and sent to Pure Data
    diff1 = [cap1.baseline_data(i)-cap1.filtered_data(i) for i in range(12)]
    print 'Diff1:', '\t'.join(map(str, diff1))
    send2Pd ('diff1: ' +  '\t'.join(map(str, diff1)) + ';')

    diff2 = [cap2.baseline_data(i)-cap2.filtered_data(i) for i in range(12)]
    print 'Diff2:', '\t'.join(map(str, diff2))
    send2Pd ('diff2: ' +  '\t'.join(map(str, diff2)) + ';')

    diff3 = [cap3.baseline_data(i)-cap3.filtered_data(i) for i in range(12)]
    print 'Diff3:', '\t'.join(map(str, diff3))
    send2Pd ('diff3: ' +  '\t'.join(map(str, diff3)) + ';')

    diff4 = [cap4.baseline_data(i)-cap4.filtered_data(i) for i in range(12)]
    print 'Diff4:', '\t'.join(map(str, diff4))
    send2Pd ('diff4: ' +  '\t'.join(map(str, diff4)) + ';')

    # Short pause before repeating loop
    time.sleep(0.1)
于 2015-03-30T17:31:04.837 回答