编辑:现在我了解了 davy 的要求(请参阅下面的评论),我将我的代码更新为这个解决方案。尽管语法相似,但它不是 FluentAssertion 扩展,但可以通过一些操作来实现。
public static class IEnumerableAssertionExtensions
{
public static void ShouldContainInWrongOrder<TSubject>(this IEnumerable<TSubject> source, IEnumerable<TSubject> expected)
{
var remaining = expected.ToList();
var inOrder = true;
foreach (var subject in source)
{
if (inOrder && !ReferenceEquals(subject, remaining[0]))
{
inOrder = false;
}
var s = subject;
Execute.Verification.ForCondition(() => remaining.Remove(s)).FailWith("Expected item in the collection: {0}", subject.ToString());
}
Execute.Verification.ForCondition(() => remaining.Count == 0).FailWith(string.Format("{0} more item{1} than expected found in the list.", remaining.Count, ((remaining.Count == 1) ? string.Empty : "s")));
Execute.Verification.ForCondition(() => !inOrder).FailWith("list items are ordered identically");
}
}
[TestClass]
public class TestFoo
{
class Thing
{
public int i;
}
[TestMethod]
public void MyMethod()
{
var a1 = new Thing { i=0 };
var a2 = new Thing { i=1 };
var a3 = new Thing { i=2 };
var a4 = new Thing { i=2 };
var list1 = new List<Thing> { a1, a2, a3 };
var list2 = new List<Thing> { a1, a2, a3 };
var list3 = new List<Thing> { a3, a2, a1 };
var list4 = new List<Thing> { a1, a2, a3, a4 };
var list5 = new List<Thing> { a3, a2 };
list1.ShouldContainInWrongOrder(list3); // Succeeds
list1.ShouldContainInWrongOrder(list2); // Fails
list1.ShouldContainInWrongOrder(list4); // Fails
list1.ShouldContainInWrongOrder(list5); // Fails
}
}