android - Android Sqlite 插入单引号 ex。“奥康纳”

Question

出于某种原因，我无法在名称字段中获取带有撇号的单引号来提交到我的 sqlite 数据库。

这是我获取输入并调用数据库函数的地方

if(fnamelabel.contains("'") || fnamelabel.contains("-")){
                    fnamelabel = DatabaseUtils.sqlEscapeString(fnamelabel);
                }else if(lnamelabel.contains("'") || lnamelabel.contains("-")){
                    lnamelabel = DatabaseUtils.sqlEscapeString(lnamelabel);                     
                }

                Log.w("myApp", "fname " + fnamelabel + ".");                        
                Log.w("myApp", "lname " + lnamelabel + ".");        

                try{
                    //if all fields are filled and has a number between 0 and 99
                    LiteHandlerPlayers db = new LiteHandlerPlayers(getApplicationContext());

                    if(db.insertLabel(fnamelabel, lnamelabel, pnumlabel)){                          
                        db.getWritableDatabase();
                        db.insertLabel(fnamelabel, lnamelabel, pnumlabel);
                        Toast.makeText(getApplicationContext(), "#" + pnumlabel + " " + fnamelabel + " " + lnamelabel + " has been added to your team.", Toast.LENGTH_SHORT).show();
                        db.close();
                    }else{
                        Toast.makeText(getApplicationContext(), "That player is already on your team!", Toast.LENGTH_SHORT).show();
                    }

这是我在数据库中的功能

if(flag){
        //no player in db with name
        ContentValues values = new ContentValues();
        values.put(Player_fname, label);
        values.put(Player_lname, label2);
        values.put(Player_num  , label3);
        values.put(Player_gplay, 0);
        values.put(Player_assist, 0);
        values.put(Player_shots, 0);
        values.put(Player_goals, 0);
        values.put(Player_shagn, 0);
        values.put(Player_gallw, 0);
        values.put(Player_assist, 0);
        db.insert(Table_labels, null, values);
        db.close();//close db
        return true;
    }else{
        db.close();
        return false;
    }       

并最终显示在不同屏幕上的微调器上，但我不断得到的错误是示例名称，如 Bob O'Connor（此时 O'Connor 已更改为 O'Connor）是附近存在语法错误O'Connor 中的 O 非常模糊。（（1）在“O”附近：语法错误，正是它所说的）如果有人能启发我，我将非常感激。