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我正在使用该MERGE语句在 sql server 2008 数据库中插入行。但是,我的 sproc 是单行操作,而实际上我更喜欢批处理这些。这甚至可能吗?如果可以,我该怎么做?

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2 回答 2

5

你可以在你的过程中使用表值参数吗?看看这里http://www.sommarskog.se/arrays-in-sql-2008.html#TVP_in_TSQL以获得一些想法

然后在过程中你可以对 TVP 使用 MERGE

于 2010-05-27T19:02:04.597 回答
3

我创建了一个名为“upsert”的过程,它接受源表名、目标表名、要加入的字段和要更新的字段(字段用逗号分隔),然后动态进行合并。

代码如下。

    CREATE proc [common].[upsert](@source nvarchar(100), @target nvarchar(100), @join_field nvarchar(100), @fields nvarchar(200))
    as

    --@source is the table name that holds the rows that you want to either update or insert into @target table
    --@join_field is the 1 field on which the two tables will be joined...you can only join on 1 field right now!
    --@fields are the comma separated fields that will either be updated or inserted into @target. They must be the same name in @source and @target


    declare @sql nvarchar(max)

    set @sql = '
        merge '+ @target +' as target
        using '+ @source +' as source
        on target.'+ @join_field +' = source.'+ @join_field +'
        when matched then
            update set
                ' + common.upsert_update_fields_string_builder('source', 'target', @fields) + '
        when not matched then
            insert ('+ @join_field +', '+ @fields +')
            values (source.'+ @join_field +',' + common.upsert_insert_fields_string_builder('source', @fields) +');
    '


    exec(@sql)







    CREATE function [common].[upsert_insert_fields_string_builder](@source nvarchar(100), @fields nvarchar(200))
    returns nvarchar(1000)
    as
    begin
    declare @string nvarchar(max)

    select @string = coalesce(
            @string + ',' + @source + '.' + items,        
            @source +'.' + items) 
    from common.split_string(@fields,',')

    return @string  
    end







    CREATE function [common].[upsert_update_fields_string_builder](@source nvarchar(100), @target nvarchar(100), @fields nvarchar(200))
    returns nvarchar(1000)
    as
    begin
    declare @string nvarchar(max)

    select @string = coalesce(
            @string + ', '+ @target + '.' + items + '=' + @source + '.' + items,        
            ''+ @target +'.' + items + '='+ @source +'.' + items) 
    from common.split_string(@fields,',')

    return @string  
    end
于 2010-05-28T00:45:28.513 回答