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我是这种加密和解密技术的新手。

我正在使用 Clickbank即时通知系统完成一项任务。我从 Clickbank 获取加密值，我想解密通知。我的问题与这个线程非常相似，但它对我不起作用。它抛出以下错误：

指定的初始化向量 (IV) 与此算法的块大小不匹配。

下面是我的解密代码。

protected void Page_Load(object sender, EventArgs e)
{
    //Sample response
    string sContent = "{\"notification\":\"18XR9s5fwkbhvfriqYS6jDJERf++jshcTDQX4NuUoUHtS+YzfMCNiEvmIVNxkbT5My2xWLFPB9mb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\",\"iv\":\"NDVEM0M4ODZGMzE4OTVENA==\"}";


    using (var reader = new StreamReader(Request.InputStream))
    {
        //Using below two lines for live testing
        //JavaScriptSerializer js = new JavaScriptSerializer();
        //sContent = reader.ReadToEnd();

        JObject jObject = JObject.Parse(sContent);

        JToken notification = jObject["notification"];
        JToken i = jObject["iv"];


        using (StreamWriter _testData = new StreamWriter(Server.MapPath("~/data.txt"), true))
        {
            _testData.WriteLine("=======================Notification"); // Write the file. 
            _testData.WriteLine(notification.ToString());
            _testData.WriteLine("=======================IV"); // Write the file. 
            _testData.WriteLine(i.ToString());

            string n = notification.ToString();
            string v = i.ToString();

            string sk = "MY SECRET KEY";


            byte[] key = Encoding.UTF8.GetBytes(sk);
            byte[] iv = Encoding.UTF8.GetBytes(v);

            try
            {
                using (var rijndaelManaged =
                       new RijndaelManaged { Key = key, IV = iv, Mode = CipherMode.CBC })
                using (var memoryStream =
                       new MemoryStream(Convert.FromBase64String(n)))
                using (var cryptoStream =
                       new CryptoStream(memoryStream,
                           rijndaelManaged.CreateDecryptor(key, iv),
                           CryptoStreamMode.Read))
                {
                    var dString = new StreamReader(cryptoStream).ReadToEnd();
                }
            }
            catch (CryptographicException ex)
            {
                Console.WriteLine("A Cryptographic error occurred: {0}", ex.Message);

            }
        }
    }
}

请让我知道我错在哪里？

谢谢

4

2 回答 2

1

我刚刚解决了这个完全相同的问题，所以这是我的解决方案。要记住的是密码/密钥由 sha1 散列，前 32 个十六进制字符用作密钥字节。让我失望的部分是字符是 c# 中的 UFT16 字符，实际上每个字符是 2 个字节，但不是源加密使用的字符。所以我所做的就是将字符串转换为具有正确字节数组的 ASCII 字符串。不是最干净的代码，但它的功能。

    public static string DecryptClickBankNotification(string cipherText, string passPhrase, string initVector)
    {
        string decryptedString = null;

        byte[] inputBytes = Encoding.UTF8.GetBytes(passPhrase);

        SHA1 sha1 = SHA1.Create();
        byte[] key = sha1.ComputeHash(inputBytes);

        StringBuilder hex = new StringBuilder(key.Length * 2);
        foreach (byte b in key)
            hex.AppendFormat("{0:x2}", b);

        string secondPhaseKey = hex.ToString().Substring(0,32);

        ASCIIEncoding asciiEncoding = new ASCIIEncoding();

        byte[] keyBytes = asciiEncoding.GetBytes(secondPhaseKey);
        byte[] iv = Convert.FromBase64String(initVector);

        try
        {
            using (RijndaelManaged rijndaelManaged = new RijndaelManaged
            { 
                Key = keyBytes,
                IV = iv,
                Mode = CipherMode.CBC, 
                Padding = PaddingMode.PKCS7})
                using (Stream memoryStream = new MemoryStream(Convert.FromBase64String(cipherText)))
                using (CryptoStream cryptoStream =
                   new CryptoStream(memoryStream,
                       rijndaelManaged.CreateDecryptor(keyBytes, iv),
                       CryptoStreamMode.Read))
            {
                decryptedString = new StreamReader(cryptoStream).ReadToEnd();
            }
        }
        catch (Exception ex)
        {
            Trace.WriteLine(new TraceData(TraceCategoryEnum.Errors, "Error decrypting message: " + ex.Message));
        }

        return decryptedString;
    }
于 2016-04-28T01:53:27.883 回答
0

If your v has 16 letters and you Encoding.UTF8.GetBytes(v); the number of bytes could be between 16 and 64. This could be giving you the error.

Specified initialization vector (IV) does not match the block size for this algorithm.

Verify that iv is 16 bytes.

于 2015-03-24T17:50:13.220 回答