这是参数解析器的列表，但它们接受字符串数组。
现在，我得到了一个字符串
-s -d "String with space" -d "string with \" escape \n the next line"
我想将字符串拆分为
-s
-d
String with space
-d
string with " escape
the next line (This is one string with \n)
有什么工具可以做到这一点吗？
也可以看看
编辑
发布为答案。
问问题
2075 次
1 回答
2
我喜欢这个答案中的ArgumentTokenizer，它只是一个类并解决了问题。
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import java.util.LinkedList;
import java.util.List;
/**
* Utility class which can tokenize a String into a list of String arguments,
* with behavior similar to parsing command line arguments to a program.
* Quoted Strings are treated as single arguments, and escaped characters
* are translated so that the tokenized arguments have the same meaning.
* Since all methods are static, the class is declared abstract to prevent
* instantiation.
*
* @version $Id$
*/
public abstract class ArgumentTokenizer
{
private static final int NO_TOKEN_STATE = 0;
private static final int NORMAL_TOKEN_STATE = 1;
private static final int SINGLE_QUOTE_STATE = 2;
private static final int DOUBLE_QUOTE_STATE = 3;
/**
* Tokenizes the given String into String tokens
*
* @param arguments A String containing one or more command-line style arguments to be tokenized.
* @return A list of parsed and properly escaped arguments.
*/
public static List<String> tokenize(String arguments)
{
return tokenize(arguments, false);
}
public static void main(String[] args)
{
for (String s : tokenize("-s -d \"String with space\" -d \"string with \\\" escape \\n the next line\""))
{
System.out.println(s);
}
}
/**
* Tokenizes the given String into String tokens.
*
* @param arguments A String containing one or more command-line style arguments to be tokenized.
* @param stringify whether or not to include escape special characters
* @return A list of parsed and properly escaped arguments.
*/
public static List<String> tokenize(String arguments, boolean stringify)
{
LinkedList<String> argList = new LinkedList<String>();
StringBuilder currArg = new StringBuilder();
boolean escaped = false;
int state = NO_TOKEN_STATE; // start in the NO_TOKEN_STATE
int len = arguments.length();
// Loop over each character in the string
for (int i = 0; i < len; i++)
{
char c = arguments.charAt(i);
if (escaped)
{
// Escaped state: just append the next character to the current arg.
escaped = false;
currArg.append(c);
} else
{
switch (state)
{
case SINGLE_QUOTE_STATE:
if (c == '\'')
{
// Seen the close quote; continue this arg until whitespace is seen
state = NORMAL_TOKEN_STATE;
} else
{
currArg.append(c);
}
break;
case DOUBLE_QUOTE_STATE:
if (c == '"')
{
// Seen the close quote; continue this arg until whitespace is seen
state = NORMAL_TOKEN_STATE;
} else if (c == '\\')
{
// Look ahead, and only escape quotes or backslashes
i++;
char next = arguments.charAt(i);
if (next == '"' || next == '\\')
{
currArg.append(next);
} else
{
currArg.append(c);
currArg.append(next);
}
} else
{
currArg.append(c);
}
break;
// case NORMAL_TOKEN_STATE:
// if (Character.isWhitespace(c)) {
// // Whitespace ends the token; start a new one
// argList.add(currArg.toString());
// currArg = new StringBuffer();
// state = NO_TOKEN_STATE;
// }
// else if (c == '\\') {
// // Backslash in a normal token: escape the next character
// escaped = true;
// }
// else if (c == '\'') {
// state = SINGLE_QUOTE_STATE;
// }
// else if (c == '"') {
// state = DOUBLE_QUOTE_STATE;
// }
// else {
// currArg.append(c);
// }
// break;
case NO_TOKEN_STATE:
case NORMAL_TOKEN_STATE:
switch (c)
{
case '\\':
escaped = true;
state = NORMAL_TOKEN_STATE;
break;
case '\'':
state = SINGLE_QUOTE_STATE;
break;
case '"':
state = DOUBLE_QUOTE_STATE;
break;
default:
if (!Character.isWhitespace(c))
{
currArg.append(c);
state = NORMAL_TOKEN_STATE;
} else if (state == NORMAL_TOKEN_STATE)
{
// Whitespace ends the token; start a new one
argList.add(currArg.toString());
currArg = new StringBuilder();
state = NO_TOKEN_STATE;
}
}
break;
default:
throw new IllegalStateException("ArgumentTokenizer state " + state + " is invalid!");
}
}
}
// If we're still escaped, put in the backslash
if (escaped)
{
currArg.append('\\');
argList.add(currArg.toString());
}
// Close the last argument if we haven't yet
else if (state != NO_TOKEN_STATE)
{
argList.add(currArg.toString());
}
// Format each argument if we've been told to stringify them
if (stringify)
{
for (int i = 0; i < argList.size(); i++)
{
argList.set(i, "\"" + _escapeQuotesAndBackslashes(argList.get(i)) + "\"");
}
}
return argList;
}
/**
* Inserts backslashes before any occurrences of a backslash or
* quote in the given string. Also converts any special characters
* appropriately.
*/
protected static String _escapeQuotesAndBackslashes(String s)
{
final StringBuilder buf = new StringBuilder(s);
// Walk backwards, looking for quotes or backslashes.
// If we see any, insert an extra backslash into the buffer at
// the same index. (By walking backwards, the index into the buffer
// will remain correct as we change the buffer.)
for (int i = s.length() - 1; i >= 0; i--)
{
char c = s.charAt(i);
if ((c == '\\') || (c == '"'))
{
buf.insert(i, '\\');
}
// Replace any special characters with escaped versions
else if (c == '\n')
{
buf.deleteCharAt(i);
buf.insert(i, "\\n");
} else if (c == '\t')
{
buf.deleteCharAt(i);
buf.insert(i, "\\t");
} else if (c == '\r')
{
buf.deleteCharAt(i);
buf.insert(i, "\\r");
} else if (c == '\b')
{
buf.deleteCharAt(i);
buf.insert(i, "\\b");
} else if (c == '\f')
{
buf.deleteCharAt(i);
buf.insert(i, "\\f");
}
}
return buf.toString();
}
}
于 2015-07-19T08:35:40.410 回答