3

在 Android 中,如何从 发送长按InstrumentationTestCase?例如,我想做一个sendKeys(KEYCODE_DPAD_CENTER)但要长按。

4

3 回答 3

2

不知道这是否是唯一/正确的方法,但我设法做到了:

public void longClickDpadCenter() throws Exception {
    getInstrumentation().sendKeySync(new KeyEvent(KeyEvent.ACTION_DOWN, KeyEvent.KEYCODE_DPAD_CENTER));
    Thread.sleep(ViewConfiguration.get(mContext).getLongPressTimeout());
    getInstrumentation().sendKeySync(new KeyEvent(KeyEvent.ACTION_UP, KeyEvent.KEYCODE_DPAD_CENTER));
}
于 2010-05-26T17:03:28.503 回答
0

您可以尝试以下辅助方法:

private void longPress(int key) {
    long downTime = SystemClock.uptimeMillis();
    long eventTime = SystemClock.uptimeMillis();
    KeyEvent event1 = new KeyEvent(downTime, eventTime, KeyEvent.ACTION_DOWN, key, 0);
    KeyEvent event2 = new KeyEvent(downTime, eventTime, KeyEvent.ACTION_DOWN, key, 1);
    getInstrumentation().sendKeySync(event1);
    getInstrumentation().sendKeySync(event2);
}

以及使用示例:

longPress(KeyEvent.KEYCODE_ENTER);
于 2015-06-15T11:52:17.537 回答
0

android 源代码中的第 179 行:

class InputKeyEvent implements InputCmd {
    @Override
    public void run(int inputSource, int displayId) {
        String arg = nextArgRequired();
        final boolean longpress = "--longpress".equals(arg);
        if (longpress) {
            arg = nextArgRequired();
        }

        do {
            final int keycode = KeyEvent.keyCodeFromString(arg);
            sendKeyEvent(inputSource, keycode, longpress, displayId);
        } while ((arg = nextArg()) != null);
    }

    private void sendKeyEvent(int inputSource, int keyCode, boolean longpress, int displayId) {
        final long now = SystemClock.uptimeMillis();
        int repeatCount = 0;

        KeyEvent event = new KeyEvent(now, now, KeyEvent.ACTION_DOWN, keyCode, repeatCount,
                0 /*metaState*/, KeyCharacterMap.VIRTUAL_KEYBOARD, 0 /*scancode*/, 0 /*flags*/,
                inputSource);
        event.setDisplayId(displayId);

        injectKeyEvent(event);
        if (longpress) {
            repeatCount++;
            injectKeyEvent(KeyEvent.changeTimeRepeat(event, now, repeatCount,
                    KeyEvent.FLAG_LONG_PRESS));
        }
        injectKeyEvent(KeyEvent.changeAction(event, KeyEvent.ACTION_UP));
    }
}
于 2020-09-26T08:31:28.713 回答