php - 获取两个日期之间的所有月份

Question

我创建了一个函数，它返回一个包含每个月的数组，从提供的碳日期开始，到当前日期结束。

尽管该功能正在做它应该做的事情，但它看起来很可怕。显然我的编程技能还没有达到应有的水平。当然必须有更好的方法来实现我想要的。

我的代码如下所示：

    class DateUtilities {
    protected $months = ['january', 'february', 'march', 'april', 'may', 'june', 'july', 'august', 'september', 'october', 'november', 'december'];

    public function getMonthListFromDate(Carbon $date)
    {
        $monthArray = array();
        $today = Carbon::today();

        $currentYear = $today->copy()->format('Y');
        $currentMonth = strtolower($today->copy()->format('F'));

        $startYear = $date->copy()->format('Y');
        $startMonth = strtolower($date->copy()->format('F'));

        for($i = $startYear; $i <= $currentYear; $i ++) {
            foreach($this->months as $monthIndex => $month) {
                if (($monthIndex >= array_search($startMonth, $this->months) && $i == $startYear) ||
                    ($monthIndex <= array_search($currentMonth, $this->months) && $i == $currentYear) ||
                    ($i != $startYear && $i != $currentYear)) {
                    $formattedMonthIndex = ($monthIndex + 1);

                    if($formattedMonthIndex < 10) {
                        $monthArray['0' . $formattedMonthIndex . '-' . $i] = $month . ' ' . $i;
                    } else {
                        $monthArray[$formattedMonthIndex . '-' . $i] = $month . ' ' . $i;
                    }
                }
            }
        }

        return $monthArray;
    }
}

结果是：

array:25 [▼
  "03-2013" => "march 2013"
  "04-2013" => "april 2013"
  "05-2013" => "may 2013"
  "06-2013" => "june 2013"
  "07-2013" => "july 2013"
  "08-2013" => "august 2013"
  "09-2013" => "september 2013"
  "10-2013" => "october 2013"
  "11-2013" => "november 2013"
  "12-2013" => "december 2013"
  "01-2014" => "january 2014"
  "02-2014" => "february 2014"
  "03-2014" => "march 2014"
  "04-2014" => "april 2014"
  "05-2014" => "may 2014"
  "06-2014" => "june 2014"
  "07-2014" => "july 2014"
  "08-2014" => "august 2014"
  "09-2014" => "september 2014"
  "10-2014" => "october 2014"
  "11-2014" => "november 2014"
  "12-2014" => "december 2014"
  "01-2015" => "january 2015"
  "02-2015" => "february 2015"
  "03-2015" => "march 2015"
]

谁能帮我改进这段代码？

编辑：

在伟大的提示之后，我得到了以下结果：

class DateUtilities {

public function getMonthListFromDate(Carbon $start)
{
    $start = $start->startOfMonth();
    $end   = Carbon::today()->startOfMonth();

    do
    {
        $months[$start->format('m-Y')] = $start->format('F Y');
    } while ($start->addMonth() <= $end);

    return $months;
}

}

谢谢你们的帮助！！

Answer 1

这次聚会迟到了，但值得补充的是，Carbon 已经涵盖了这一点。使用 CarbonPeriod 会将整个班级减少到...

use Carbon\Carbon;
use Carbon\CarbonPeriod;

class DateUtilities
{
    public function getMonthListFromDate(Carbon $start)
    {
        foreach (CarbonPeriod::create($start, '1 month', Carbon::today()) as $month) {
            $months[$month->format('m-Y')] = $month->format('F Y');
        }
        return $months;
    }
}

Answer 2

使用 DateTime 这可以很容易地实现。

1. 为每个开始和结束日期创建一个日期时间对象
2. 设置1个月的间隔
3. 获取开始日期和结束日期之间的一组日期，间隔为 1 个月

例子 ：

public function getMonthListFromDate(Carbon $date)
{
    $start    = new DateTime(); // Today date
    $end      = new DateTime($date->toDateTimeString()); // Create a datetime object from your Carbon object
    $interval = DateInterval::createFromDateString('1 month'); // 1 month interval
    $period   = new DatePeriod($start, $interval, $end); // Get a set of date beetween the 2 period

    $months = array();

    foreach ($period as $dt) {
        $months[] = $dt->format("F Y");
    }

    return $months;
}

在行动中看到它：http: //3v4l.org/smS3N

Answer 3

使用 CarbonPeriod 类 todo 相同

$period = \Carbon\CarbonPeriod::create('2018-06-01', '1 month', '2019-06-01');

foreach ($period as $dt) {
     echo $dt->format("Y-m") . "<br>\n";
}

Answer 4

这是一个更短更简单的示例。您可以轻松地将其调整为 Carbon 类的约定：

$start = strtotime('last month', strtotime('2013-03'));
$now = time();

while(($start = strtotime('next month', $start)) <= $now) {
    $result[date('m-Y', $start)] = strtolower(date('F Y', $start));
}

Answer 5

while ($start->lte($end)) {
            $months[$start->format('m-Y')] = $start->format('F Y');
            $start->addMonth();
        }
        return $months;