我被这个任务卡住了：用目标代码编写一个程序，将 3 位二进制数转换为十进制数。例如，如果输入为 101，则输出应为 5；如果输入为 011，则输出应为 3。这是我目前的代码：
49 00 50 - Input char 1
49 00 51 - Input char 2
49 00 53 - Input char 3
c0 00 00 - 0 memory
d1 00 50 - Load char 1
80 00 48 - subtract 48 cose 0 is 48 in dec
1c - shift to left
1c - shift to left again cose 3rd position in binary is x4
e1 00 60 - store int 1
d1 00 51 - load char 2
80 00 48 - subtract 48 cose 0 is 48 in dec
1c - shift to left cose 2nd position in binary is x2
e1 00 62 - store int 2
d1 00 53 - load char 3
80 00 48 - subtract 48 cose 0 is 48 in dec
71 00 60 - add int 1
71 00 62 - add int 2
f1 00 64 - store char
51 00 64 - output character
00
zz
有人可以帮助我并指导我如何做到这一点，请记住我两周前才开始使用 pep8。谢谢