最近我一直在尝试在 minecraft 服务器(使用 Java 运行)和从头开始(使用 JavaScript 运行)之间进行通信。我已经用java编写了代码:
package me.yotam180;
import java.io.IOException;
import java.io.OutputStream;
import java.net.InetSocketAddress;
import java.util.HashMap;
import java.util.Map;
import org.bukkit.Bukkit;
import com.sun.net.httpserver.HttpExchange;
import com.sun.net.httpserver.HttpHandler;
import com.sun.net.httpserver.HttpServer;
public class HttpProcessor {
public MainClass plugin;
public HttpProcessor (MainClass plug) throws IOException {
plugin = plug;
plugin.getLogger().info("CREATED HTTTP PROCESSOR");
HttpServer server = HttpServer.create(new InetSocketAddress(9090), 0);
server.createContext("/pollplayer", new PollPlayerHandler());
server.createContext("/killplayer", new KillPlayerHandler());
plugin.getLogger().info("STARTED HTTTP SERVER");
server.setExecutor(null); // creates a default executor
server.start();
}
static class PollPlayerHandler implements HttpHandler {
@SuppressWarnings("deprecation")
@Override
public void handle(HttpExchange httpExchange) throws IOException {
// TODO Auto-generated method stub
Map <String,String>parms = HttpProcessor.queryToMap(httpExchange.getRequestURI().getQuery());
StringBuilder response = new StringBuilder();
response.append(Bukkit.getPlayer(parms.get("name")).getLocation().toString());
HttpProcessor.writeResponse(httpExchange, response.toString());
}
}
static class KillPlayerHandler implements HttpHandler {
@SuppressWarnings("deprecation")
@Override
public void handle(HttpExchange httpExchange) throws IOException {
// TODO Auto-generated method stub
Map <String,String>parms = HttpProcessor.queryToMap(httpExchange.getRequestURI().getQuery());
Bukkit.getPlayer(parms.get("name")).setHealth(0);
HttpProcessor.writeResponse(httpExchange, "SUCCESS");
}
}
public static void writeResponse(HttpExchange httpExchange, String response) throws IOException {
httpExchange.sendResponseHeaders(200, response.length());
OutputStream os = httpExchange.getResponseBody();
os.write(response.getBytes());
os.close();
}
public static Map<String, String> queryToMap(String query){
Map<String, String> result = new HashMap<String, String>();
for (String param : query.split("&")) {
String pair[] = param.split("=");
if (pair.length>1) {
result.put(pair[0], pair[1]);
}else{
result.put(pair[0], "");
}
}
return result;
}
}
现在我必须制作临时 HTTP 客户端。我尝试的每一种方法,它都不起作用。我尝试打开我的浏览器,我写了http://localhost:9090/pollplayer?name=yotam_salmon并且它漂亮地报告了我的播放器位置。现在我的问题是从头开始的 JS。
这里是:
new (function () {
var ext = this;
// Cleanup function when the extension is unloaded
ext._shutdown = function () { };
// Status reporting code
// Use this to report missing hardware, plugin or unsupported browser
ext._getStatus = function () {
return { status: 2, msg: 'Ready' };
};
ext.get_Player = function (name, callback) {
//in this function i need to call http://localhost:9090/pollplayer?name= + name, wait for the response and then callback it.
//the response can't be "return response;", and it cannot be call backed from another function. If this function was called, it
//has to report the location back as a string
};
// Block and block menu descriptions
var descriptor = {
blocks: [
['R', 'location of %s', 'get_Player', 'Player'],
]
};
// Register the extension
ScratchExtensions.register('ScratchCraft', descriptor, ext);
})();
我无法以不同的方式格式化我的 JS 代码,因为 Scratch 仅适用于这种格式。(此处解释:http: //llk.github.io/scratch-extension-docs/)。在ext.get_Player
函数中,我必须访问 Java http 服务器,请求/pollplayer?name= + name
并回调它。
我很乐意得到解决方案:) 谢谢!