我认为这会奏效,但遗憾的是它没有。我得到了错误-
ArrayList 类型中的方法 add(CustomerInfo) 不适用于参数 (String)
我的目标是返回一个Arraylist
并使用 get 方法进行访问。当我使用 String 时Arraylist
,我不能使用 arr.get(i) .userID , ... .FirstName ...
类 CustomerInfo.java
public class CustomerInfo {
private static Connection conn = null;
private static ResultSet resultSet = null;
public String UserID;
public String FirstName;
public String SecondName;
public ArrayList<CustomerInfo> findCustomer (String userID) throws SQLException {
conn = null;
PreparedStatement pstmt = null;
try {
JDBCConnection jdbcConn = new JDBCConnection();
conn = jdbcConn.openConnection();
ArrayList<CustomerInfo> customerList new ArrayList<CustomerInfo();
String sql = "SELECT USERID FROM TAB0025 WHERE USERID = ?";
pstmt = conn.prepareStatement(sql);
pstmt.setString(1, userID);
resultSet = pstmt.executeQuery();
while (resultSet.next()) {
customerList.add(resultSet.getString("USERID"));
customerList.add(resultSet.getString("FIRSTNAME"));
customerList.add(resultSet.getString("SECONDNAME"));
this.UserID = resultSet.getString("USERID");
this.FirstName = resultSet.getString("FIRSTNAME");
this.SecondName resultSet.getString("SECONDNAME");
}
return customerList;
} catch (Exception e) {
throw e;
}
finally {
conn.close();
}
public String getUserID() {
return this.UserID;
}
public String getFirstname() {
return this.FirstName;
}
public String getSecondName() {
return this.SecondName;
}
}
类 InputReader.java
// ...
if (CustomerInfo.ExsistUserID(this.UserID)) {
CustomerInfo edit = new CustomerInfo();
ArrayList<CustomerInfo> arr = new ArrayList<CustomerInfo>();
arr = edit.findCustomer(this.UserID);
System.out.println("UserID: "+ arr.get(0).getUserID() + " First Name: "arr.get(0).getFirstName() + " Second Name: " arr.get(0).getSecondName());
}
// ...