给定
void* hello () {
cout << "Test.\n";
}
和
struct _table_struct {
void *(*hello) ();
};
我们如何将函数(hello)分配给函数成员指针?
我试过这个(主要):
_table_struct g_table;
_table_struct *g_ptr_table = &g_table;
// trying to get the struct member function pointer to point to the designated function
(*(g_ptr_table)->hello) = &hello; // this line does not work
// trying to activate it
(*(g_ptr_table)->hello)();