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我正在开发一个预订应用程序，我正在创建一个查询，按月计算酒店的入住率。为此，我必须检查所有预订的入住和退房日期，并增加一些变量并将它们与相应的月份相关联。我只需要在当年测量这个比率。如果预订的结帐日期或入住日期是三月（例如），我需要增加对应于该月职业的变量。我需要为该年间隔内的每次预订执行此操作。

Booking 有签入日期和签出日期，其他属性与本次查询无关，输入参数为 BeginDate (2015-01-01 ) 和 EndDate (2015-12-31)。

Month       Ocupation
[JANUARY] | 29
[FEBRUARY] | 20
[MARCH] | 30
....... | ...

这就是我到目前为止所做的，此刻我有点迷失了。任何帮助，将不胜感激。

   Select  
        SUM(CASE WHEN datename(month, [CheckIn]) = 'January' or datename(month, [CheckOut]) = 'January' THEN 1 ELSE 0 END)  January,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'February' or datename(month, [CheckOut]) = 'February' THEN 1 ELSE 0 END) February,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'March' or datename(month, [CheckOut]) = 'March' THEN 1 ELSE 0 END) March,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'April' or datename(month, [CheckOut]) = 'April' THEN 1 ELSE 0 END)  April,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'May' or datename(month, [CheckOut]) = 'May' THEN 1 ELSE 0 END)  May,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'June' or datename(month, [CheckOut]) = 'June' THEN 1 ELSE 0 END) June,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'July' or datename(month, [CheckOut]) = 'July' THEN 1 ELSE 0 END) July,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'August' or datename(month, [CheckOut]) = 'August' THEN 1 ELSE 0 END) August,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'September' or datename(month, [CheckOut]) = 'September' THEN 1 ELSE 0 END) September,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'October' or datename(month, [CheckOut]) = 'October' THEN 1 ELSE 0 END) October,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'November' or datename(month, [CheckOut]) = 'November' THEN 1 ELSE 0 END) November,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'December' or datename(month, [CheckOut]) = 'December' THEN 1 ELSE 0 END) December
FROM {Booking} INNER JOIN {Status} ON {Booking}.[StatusId] = {Status}.[Id]
WHERE {Booking}.[CheckIn] >= @BeginDate AND {Booking}.[CheckOut]  <= @EndDate AND {Status}.[Label] <> 'Canceled'
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1 回答 1

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假设您想将 CheckIn 和 CheckOut 发生在同一个月的预订作为该月的 1 个职业计算，并且将在不同月份有 CheckIn 和 CheckOut 的预订作为每个月的 1 个，那么这个查询应该可以工作：

SELECT 
    Month, 
    'Occupation' = COUNT(MonthNo)
FROM Booking 
OUTER APPLY (
    SELECT MonthNo, Month FROM (
       VALUES (1, 'January'), (2, 'February'), (3, 'March'),(4, 'April'), (5, 'May')
    ) AS Months (MonthNo, Month) 
    WHERE MonthNo BETWEEN MONTH(CheckIn) AND MONTH(CheckOut)
) c
-- WHERE CheckIn >= @BeginDate 
--   AND CheckOut  <= @EndDate 
--   AND [Status].[Label] <> 'Canceled' 
GROUP BY Month, MonthNo ORDER BY MonthNo

我使用了一个表值构造函数来制作带有内联月份数字和名称的表，但是如果您已经有一个合适的日历表（您应该），那么请改用它。

给定一个输入表，如：

Id  CheckIn     CheckOut
1   2015-01-30  2015-03-31 -- 1 for Jan, Feb, Mar
2   2015-01-03  2015-01-05 -- 1 for Jan
3   2015-01-30  2015-02-05 -- 1 for Jan, Feb
4   2015-01-30  2015-01-31 -- 1 for Jan
5   2015-02-01  2015-02-03 -- 1 for Feb
6   2015-03-22  2015-04-01 -- 1 for Mar, Apr
7   2015-03-23  2015-04-03 -- 1 for Mar, Apr
8   2015-03-30  2015-03-31 -- 1 for Mar
9   2015-04-01  2015-04-03 -- 1 for Apr
10  2015-04-28  2015-05-01 -- 1 for Apr, May
11  2015-05-01  2015-05-03 -- 1 for May

它会产生如下输出：

Month   Occupation
January     4
February    3
March       4
April       4
May         2
于 2015-03-10T14:21:21.753 回答