您必须将 QUERY 调用到 yahoo 天气 api,您似乎忽略了它。查询现在设置为 * 以便它可以返回除风之外的其他数据。加上一个变量 var location 被分配到查询中以覆盖所有区域。使用美国地区的州名,例如。城市盒子里的纽约,乡村盒子里的纽约。
<!DOCTYPE html>
<html>
<head>
<script>
function getLocation() {
var city = document.getElementById("city").value;
var country = document.getElementById("country").value;
var location = city + "," + country;
//create a script and add it to your page
var script = document.createElement('script');
script.src = "https://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text='" + location + "')&format=json&callback=callbackFunction";
document.getElementsByTagName('head')[0].appendChild(script);
}
var callbackFunction = function(data) {
var wind = data.query.results.channel.wind;
var wind_chill = wind.chill;
var wind_speed = wind.speed;
var wind_direction = wind.direction
document.getElementById("chill").innerHTML = wind_chill;
document.getElementById("speed").innerHTML = wind_speed;
document.getElementById("direction").innerHTML = wind_direction;
//alert(wind.chill);
}
</script>
</head>
<body>
City:<input type="text" id="city">
Country/State in U.S.A<input type="text" id="country">
<input type="button" onclick="getLocation()" value="Get Weather">
<p>Wind Chill</p>
<p id="chill"></p>
<p>Wind Speed</p>
<p id="speed"></p>
<p>Wind Direction</p>
<p id="direction"></p>
</body>
</html>
贡献者 Brian Glaz 帮我解决了这个问题,向我展示了如何将 var 位置分配给查询以及如何在输入数据后调用查询。