所以我有以下场景来创建我的 docker 镜像和容器。问题是：如何在容器启动时启动我的流程？
1. create image
cat /var/tmp/mod_sm.tar | docker import - mod_sm_39
2. see images
[root@sl1cdi151 etc]# docker images
REPOSITORY TAG IMAGE ID CREATED VIRTUAL SIZE
mod_sm_39 latest 1573470bfa06 2 hours ago 271 MB
mod_site_m0305 latest c029826a2253 4 days ago 53.8 MB
<none> <none> ee67b9aec2d3 4 days ago 163.4 MB
mod_site_soft latest 0933a386d56c 6 days ago 53.8 MB
mod_site_vm151 latest 4461c32e4772 6 days ago 53.8 MB
3. create container
docker run -it --net=host -v /root:/root -v /usr/share/Modules:/usr/share/Modules -v /usr/libexec:/usr/libexec -v /var:/var -v /tmp:/tmp -v /bin:/bin -v /cgroup:/cgroup -v /dev:/dev -v /etc:/etc -v /home:/home -v /lib:/lib -v /lib64:/lib64 -v /sbin:/sbin -v /usr/lib64:/usr/lib64 -v /usr/bin:/usr/bin --name="mod_sm_39_c2" -d mod_sm_39 /bin/bash
4. now in container i go to my application and start the following:
[root@sl1cdi151 ven]# ./service.sh sm_start
5. check if it's up
[root@sl1cdi151 etc]# ps -ef | grep http
root 33 1 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
daemon 34 33 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
daemon 36 33 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
daemon 37 33 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
daemon 39 33 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
daemon 41 33 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
daemon 43 33 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
daemon 45 33 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
daemon 47 33 0 11:15 ? 00:00:00 ./httpd -k start -f /usr/local/clo/ven/mod_web/httpd/conf/httpd.conf
root 80 1 0 13:32 pts/2 00:00:00 grep http
所以我需要"./service.sh sm_start"在容器启动时启动它。我该如何实现。先感谢您