java - 将 LinkedHashset 内容复制到新的 ArrayList？

Question

我有一个 listView 最初有一些内容。如果它得到相同的内容，我通过删除重复linkedhashset。现在，我想将linkedhashset内容（即不重复内容）复制到新的ArrayList.

我试图通过复制

p.addAll(0,lhm);  // P is the instance of  ArrayList and lhm is linkedHashset instance

但是，ArrayList也包括重复内容。

例子：

 ArrayList<Price> p = new ArrayList<Price>();

     p.add(new Price("Banana", 60));
     p.add(new Price("Apple", 80));

    LinkedHashSet<Price> lhm = new LinkedHashSet<Price>(p); 
    lhm.add(new Price("Banana", 20)); 
    lhm.add(new Price("Apple", 40));
    lhm.add(new Price("Orange", 30)); 
    for(Price pr:lhm)
    {
        System.out.println(pr);
    } 
    Price duplicate = new Price("Banana", 20);
    System.out.println("inserting duplicate object..."); 
    lhm.add(duplicate);
    lhm.add(new Price("Apple", 40));
    p.addAll(0,lhm);
    System.out.println("After insertion:"); 
    for(Price pr:lhm)
    {
        System.out.println(pr);
    }

    for (int i = 0; i < p.size(); i++) {

        System.out.println(p.get(i).getItem() +"-" +p.get(i).getPrice());           
    }

价格等级

class Price
{
    private String item; 
    private int price; 
    public Price(String itm, int pr)
    {
        this.item = itm; 
        this.price = pr; 
        }
    public int hashCode()
    { 
        System.out.println("In hashcode");
        int hashcode = 0; 
        hashcode = price;
        //System.out.println(hashcode);

        hashcode+= item.hashCode(); 
    //  System.out.println(hashcode);

        return hashcode;  
        }

    public boolean equals(Object obj)
    {
        System.out.println("In equals"); 
        if (obj instanceof Price) 
        {
            Price pp = (Price) obj; 
            return (pp.item.equals(this.item) && pp.price == this.price); 
            }
        else 
        { 
            return false;
            }
        }

    public String getItem()
    {
        return item; 
    }

    public void setItem(String item) 
    { 
        this.item = item; 
        }

    public int getPrice() 

    {
        return price;
        }
    public void setPrice(int price) 
    {
        this.price = price; 
        }
    public String toString()
    {
        return "item: "+item+" price: "+price; 
        }
    }

输出：

In hashcode
In hashcode
In hashcode
In hashcode
In hashcode
item: Banana price: 60
item: Apple price: 80
item: Banana price: 20
item: Apple price: 40
item: Orange price: 30
inserting duplicate object...
In hashcode
In equals
In hashcode
In equals
//iterating linkedhasset content

After insertion:
item: Banana price: 60
item: Apple price: 80
item: Banana price: 20
item: Apple price: 40
item: Orange price: 30

// iterating ArrayList p content

Banana-60
Apple-80
Banana-20
Apple-40
Orange-30
Banana-60
Apple-80 <-- duplicate

score 8 · Accepted Answer

以下行只是从第 0 个索引开始将所有元素插入到数组列表中

p.addAll(0,lhm);

而且，使用这些行添加的元素仍然存在于 arraylist 中：

p.add(new Price("Banana", 60));
p.add(new Price("Apple", 80));

因此，您应该在从linkedhashset 添加项目之前清除数组列表，以防您不想要重复项。IE

p.clear();
p.addAll(lhm); // and, at this point you don't need the index.

score 4 · Accepted Answer

See this full solution may be help you

import java.util.ArrayList;
import java.util.LinkedHashSet;
import java.util.List;
import java.util.Set;
public class LinkedHashSetToList {

        public static void main(String[] args) {
        Set<String> lhs = new LinkedHashSet<String>();
        lhs.add("mumbai");
        lhs.add("delhi");
        lhs.add("kolkata");
        lhs.add("chandigarh");
        lhs.add("dehradun");
        //print linkedhashset
        System.out.println("lhs is = "+lhs);
        List<String> list = new ArrayList<String>(lhs);
        // print arraylist
        System.out.println("ArrayList Is = "+list);

    }

}

Output:

lhs is = [mumbai, delhi, kolkata, chandigarh, dehradun]
ArrayList Is = [mumbai, delhi, kolkata, chandigarh, dehradun]

Reference : How to Convert a LinkedHashSet to ArrayList

score 2 · Accepted Answer

A Set will only ensure that its own elements are unique. You can't expect ArrayList to exclude duplicates unless the entire collection is filtered through a set. For example:

...
p.addAll(0,lhm);
p = new ArrayList<String>(new HashSet<String>(p));

java - 将 LinkedHashset 内容复制到新的 ArrayList？

3 回答 3

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