我试图从数组中取出长双精度数。
long double num;
char * pEnd;
char line[] = {5,0,2,5,2,2,5,4,5,.,5,6,6};
num = strtold(line1, &pEnd);
出于某种原因,我得到的数字四舍五入到 502522545.6 我对 C++ 很陌生,所以我做错了什么吗?需要做什么才能获得 num 中的整个数字而不是四舍五入?
感谢您的帮助 !!!
抱歉,这是我在这里的第一篇文章 =)
所以整个程序代码如下:
class Number
{
private:
long double num ;
char line[19], line2[19];
int i, k;
public:
Number()
{}
void getData()
{
i = 0;
char ch= 'a';
cout << "\nPlease provide me with the number: ";
while ((ch = _getche()) != '\r')
{
line[i] = ch;
line2[i] = ch;
i++;
}
}
void printData() const
{
cout << endl;
cout << "Printing like an Array: ";
for (int j = 0; j < i; j++)
{
cout << line[j];
}
cout << "\nModified Array is: ";
for (int j = 0; j < (i-k); j++)
{
cout << line2[j];
}
cout << "\nTHe long Double is: " << num;
}
void getLong()
{
char * pEnd;
k = 1;
for (int j = 0; j < i; j++)
{
if (line2[j+k] == ',')
{
k++;
line2[j] = line2[j + k];
}
line2[j] = line2[j + k];
}
line2[i -k] = line2[19];
num = strtold(line2, &pEnd);
}
};
int main()
{
Number num;
char ch = 'a';
while (ch != 'n')
{
num.getData();
num.getLong();
num.printData();
cout << "\nWould you like to enter another number ? (y/n)";
cin >> ch;
}
return 0;
}
想法是输入的数字采用以下格式($50,555,355.67)或任何其他数字。然后程序会删除除数字和“。”之外的所有符号。然后我试图从数组中取出 long double num 。如果你运行程序,你总是会从 num 中得到四舍五入的数字。