11

我是 IE11 中的 Bootstrap Select 用户。

当我用 ajax 填充数据并打开它时,它会自动向下移动,当我选择任何值时,它不会被选中。如何消除此错误?

jQuery.ajax({
        url: base_url + "UserBusinesses/ajaxState/" + countryId,
        dataType: 'json',
        beforeSend: function () {
            $('#UserBusinessStateId').html('<option value="">Loding... </option>');
            $('#UserBusinessStateId').selectpicker('refresh');
            $('#UserBusinessCityId').html('<option value="">Select city</option>');
            $('#UserBusinessCityId').selectpicker('refresh');
        },
        success: function (obj) {
            var addHtml = '';
            addHtml += '<option value="">Select state</option>';
            $.each(obj, function (key, value) {
                var selected = "";
                if (selectedState == key) {
                    var selected = "selected='selected'";
                }
                addHtml += "<option value='" + key + "' " + selected + ">" + value + "</option>";
            });
            jQuery("#UserBusinessStateId").html(addHtml);

            $('#UserBusinessStateId').selectpicker('refresh');

        }
    });
4

1 回答 1

15

我在 IE 中遇到了这个问题,我找到了解决方案

 $('#UserBusinessStateId').selectpicker('refresh');

删除这个并添加这个代码

$('#UserBusinessStateId').selectpicker('render').selectpicker('refresh');
于 2015-03-11T10:21:57.043 回答