我正在使用 gcc-arm-none-eabi 4.9 2014q4 为 Cortex-M4 编写裸机应用程序。当应用程序加载第一个调用_sbrk
似乎是无效的。
我已经实现_sbrk
如下:
extern unsigned int _start_of_heap;
extern unsigned int _end_of_heap;
caddr_t heap = (caddr_t)&_start_of_heap;
#include "hardware/uart.h"
// low level bulk memory allocator - used by malloc
caddr_t _sbrk ( int increment ) {
caddr_t prevHeap;
caddr_t nextHeap;
send_str("_sbrk(");
send_dec(increment);
send_str(")\n");
prevHeap = heap;
// Always return data aligned on a 8 byte boundary
nextHeap = (caddr_t)(((unsigned int)(heap + increment) + 7) & ~7);
// get current stack pointer
register caddr_t stackPtr asm ("sp");
send_str("\tstackPtr(");
send_hex((uint32_t)stackPtr);
send_str(")\n");
send_str("\tprevHeap(");
send_hex((uint32_t)prevHeap);
send_str(")\n");
// Check enough space and there is no collision with stack coming the other way
// if stack is above start of heap
if((nextHeap < stackPtr) && (nextHeap >= (caddr_t)&_start_of_heap) && (nextHeap < (caddr_t)&_end_of_heap)) {
heap = nextHeap;
return (caddr_t) prevHeap;
}
send_str("*\n");
return NULL; // error - no more memory
}
链接器定义堆限制如下:
MEMORY
{
SRAM_L (rwx) : ORIGIN = 0x00000000, LENGTH = 32K
SRAM_U (rwx) : ORIGIN = 0x20000000, LENGTH = 32K
}
SECTIONS
{
.vectors 0x00000000 :
{
*o(.vectors_)
} >SRAM_L
.text :
{
. = ALIGN (4);
*(.text);
} >SRAM_L
. = . ;
_datai = . ;
.data :
{
. = ALIGN (4);
_data = . ; *(.data .data.*); _edata = . ;
} >SRAM_U AT >SRAM_L
.data_init :
{
_edatai = .;
} >SRAM_L
.bss :
{
. = ALIGN (4);
_bss = . ; *(.bss) *(COMMON); _ebss = . ;
} >SRAM_U
. = ALIGN (4);
. += 8;
free_memory_start = .;
_end_of_stack = .;
end = .;
_start_of_heap = .;
. = 0x20007000;
_start_of_stack = .;
_end_of_heap = .;
}
程序代码运行快速堆栈和堆测试:
extern unsigned int _start_of_heap;
extern unsigned int _end_of_heap;
extern caddr_t heap;
void foo(uint8_t i)
{
unsigned long blah = 0;
unsigned long * halb;
halb = malloc(sizeof(unsigned long));
iprintf("blah(%08x) halb(%08x) heap(%08x)\n", &blah, halb, heap);
if(i)
foo(i - 1);
free(halb);
}
int main(int argc, char ** argv)
{
init_uart((void*)UART2_IPS_BASE_ADDR, 115200);
iprintf("Heap test (%08x - %08x)\n", &_start_of_heap, &_end_of_heap);
foo(10);
return 0;
}
产生以下输出:
_sbrk(1040965006) <----- Note large size
stackPtr(20006E18)
prevHeap(2000089C)
* <----- '*' indicates out of range
_sbrk(626)
stackPtr(20006E18)
prevHeap(2000089C)
Heap test (2000089c - 20007000)
blah(20006fb8) halb(00000410) heap(20000b10)
blah(20006fa0) halb(00000420) heap(20000b10)
blah(20006f88) halb(00000430) heap(20000b10)
blah(20006f70) halb(00000440) heap(20000b10)
blah(20006f58) halb(00000450) heap(20000b10)
blah(20006f40) halb(00000460) heap(20000b10)
blah(20006f28) halb(00000470) heap(20000b10)
blah(20006f10) halb(00000480) heap(20000b10)
blah(20006ef8) halb(00000490) heap(20000b10)
blah(20006ee0) halb(000004a0) heap(20000b10)
blah(20006ec8) halb(000004b0) heap(20000b10)
第一次分配是 1040965006 字节,这似乎不正确并且失败了。在此之后,我假设malloc
继续分配 626 个字节。malloc
对for 的每个后续调用halb
似乎都返回了一个超出我的堆栈范围的地址。这个第一次调用看起来像一个错误,还是应该被忽略,如果是,返回的地址是malloc
怎么回事?
谢谢,德文