1

我正在尝试创建一个返回值的函数。

在我的函数中，我有这个脚本：

WITH t_new AS
    (
      SELECT PersIDOLD, PersIDNEW, RightsMUT,
      SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp

      FROM
        (
          SELECT h1.*,
            CASE
              WHEN h1.PersIDNEW = lag(h1.PersIDNEW) 
                                    over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
                OR h1.PersIDOLD = lag(h1.PersIDOLD) 
                                    over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
              THEN 0
              ELSE 1
            END gap
          FROM HelpTable1 h1

        )
    )
  SELECT PERSIDNEW, RIGHTSMUT
  FROM t_new
  WHERE grp =
    (
      SELECT grp FROM t_new WHERE PersIDNEW = 12 -- going to be a variable
    )

回报是这样的：

http://img59.imageshack.us/img59/6733/tablei.gif

现在我想返回row 3因为它有一个1连续的 RightsMUT

我怎么能这样做？我试图用 2 来做，With但 oracle 还不支持 2。

4

2 回答 2

0

让我尝试猜测 - 请检查以下内容是否为您提供所需的内容：

WITH t_new AS
(
  SELECT PersIDOLD, PersIDNEW, RightsMUT,
  SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp

  FROM
    (
      SELECT h1.*,
        CASE
          WHEN h1.PersIDNEW = lag(h1.PersIDNEW) 
                                over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
            OR h1.PersIDOLD = lag(h1.PersIDOLD) 
                                over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
          THEN 0
          ELSE 1
        END gap
      FROM HelpTable1 h1

    )
) 
SELECT PERSIDNEW, RIGHTSMUT
FROM t_new
WHERE PersIDNEW = 12 AND RightsMUT = 1
于 2010-05-21T10:19:21.657 回答
0

我的解决方案：

  WITH t_new AS
    (
      -- Alles durch gehen und
      SELECT PersIDOLD, PersIDNEW, RightsMUT, SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
      FROM
        (
          SELECT h1.*,
            CASE
              WHEN h1.PersIDNEW = lag(h1.PersIDNEW) over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
                OR h1.PersIDOLD = lag(h1.PersIDOLD) over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
              THEN 0
              ELSE 1
            END gap
          FROM LUTAXKT.HILFSTABELLE1UMSETZUNG h1
            --WHERE h1.updateflag = 0
        )
    )
  SELECT PersIDNEW, RightsMUT
  FROM t_new
  WHERE  RightsMUT = 1 and
   grp =
    (
      SELECT grp FROM t_new WHERE PersIDNEW = 12
    )
于 2010-05-21T11:11:24.387 回答