我想向自己发送电子邮件,但在页面http://localhost:3000/panic上出现错误并包含错误 url -/panic
在我们的例子中。但我不知道如何从c martini.Context
内部RecoverWrap
方法获取 url。
package main
import (
"errors"
"github.com/go-martini/martini"
"net/http"
)
func main() {
m := martini.Classic()
m.Use(RecoverWrap)
m.Get("/panic", func() {
panic("some panic")
})
m.Get("/", func(req *http.Request, res http.ResponseWriter) {
res.Write([]byte("mainPage"))
})
m.Run()
}
func RecoverWrap(c martini.Context, w http.ResponseWriter) {
var err error
defer func(w http.ResponseWriter) {
r := recover()
if r != nil {
switch t := r.(type) {
case string:
err = errors.New(t)
case error:
err = t
default:
err = errors.New("Unknown error")
}
// how to get request url here
// I want to send email with error url
http.Error(w, "Something goes wrong", http.StatusInternalServerError)
}
}(w)
c.Next()
}