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Is there a way to change the options in list.js without creating a new object? Looking through the documentation it seems the only way to set them is in the constructor. That works, but if I can avoid creating another object each time the user changes an option (what fields are being searched/filtered on), I'd rather re-use the same one.

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您应该能够使用直接 DOM 操作来操作目标项目,您还可以查看它们的现有列表 + 添加示例

于 2015-02-27T23:47:52.327 回答