58

I have a file which contains data in the following format

1
2
3

I want to load this to map as {(1->1), (2->1), (3->1)}

This is the Java 8 code,

Map<Integer, Integer> map1 = Files.lines(Paths.get(inputFile))
                .map(line -> line.trim())
                .map(Integer::valueOf)
                .collect(Collectors.toMap(x -> x, x -> 1));

I am getting the following error

Exception in thread "main" java.lang.IllegalStateException: Duplicate key 1

How do I fix this error?

4

2 回答 2

56

The pramodh's answer is good if you want to map your value to 1. But in case you don't want to always map to a constant, the use of the "merge-function" might help:

Map<Integer, Integer> map1 = Files.lines(Paths.get(inputFile))
                .map(line::trim())
                .map(Integer::valueOf)
                .collect(Collectors.toMap(x -> x, x -> 1, (x1, x2) -> x1));

The above code is almost the same as posted in the question. But if it encounters a duplicate key, instead of throwing an exception, it will solve it by applying the merge function, by taking the first value.

于 2018-05-24T08:49:06.047 回答
26

The code will run if there are no duplicates in the file.

Map<Integer, Integer> map1 = Files.lines(Paths.get(inputFile))
            .map(String::trim)
            .map(Integer::valueOf)
            .collect(Collectors.toMap(x -> x, x -> 1));

If there are duplicates use the following code to get the total number of occurrences in the file for that key.

Map<Integer, Long> map1 = Files.lines(Paths.get(inputFile))
            .map(String::trim)
            .map(Integer::valueOf)
            .collect(Collectors.groupingBy(x -> x, Collectors.counting());
于 2015-02-27T22:10:11.117 回答