#define TRUE 1
#define FALSE 0
int days_in_month[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
char *months[]=
{
" ",
"\n\n\nJanuary",
"\n\n\nFebruary",
"\n\n\nMarch",
"\n\n\nApril",
"\n\n\nMay",
"\n\n\nJune",
"\n\n\nJuly",
"\n\n\nAugust",
"\n\n\nSeptember",
"\n\n\nOctober",
"\n\n\nNovember",
"\n\n\nDecember"
};
int inputyear(void)
{
int year;
printf("Please enter a year (example: 1999) : ");
scanf("%d", &year);
return year;
}
int determinedaycode(int year)
{
int daycode;
int d1, d2, d3;
d1 = (year - 1.)/ 4.0;
d2 = (year - 1.)/ 100.;
d3 = (year - 1.)/ 400.;
daycode = (year + d1 - d2 + d3) %7;
return daycode;
}
int determineleapyear(int year)
{
if(year% 4 == FALSE && year%100 != FALSE || year%400 == FALSE)
{
days_in_month[2] = 29;
return TRUE;
}
else
{
days_in_month[2] = 28;
return FALSE;
}
}
void calendar(int year, int daycode)
{
int month, day;
for ( month = 1; month <= 12; month++ )
{
printf("%s", months[month]);
printf("\n\nSun Mon Tue Wed Thu Fri Sat\n" );
// Correct the position for the first date
for ( day = 1; day <= 1 + daycode * 5; day++ )
{
printf(" ");
}
// Print all the dates for one month
for ( day = 1; day <= days_in_month[month]; day++ )
{
printf("%2d", day );
// Is day before Sat? Else start next line Sun.
if ( ( day + daycode ) % 7 > 0 )
printf(" " );
else
printf("\n " );
}
// Set position for next month
daycode = ( daycode + days_in_month[month] ) % 7;
}
}
int main(void)
{
int year, daycode, leapyear;
year = inputyear();
daycode = determinedaycode(year);
determineleapyear(year);
calendar(year, daycode);
printf("\n");
}
此代码在终端中生成输入年份的日历。我的问题是如何将其转换为 Objective-C 语法而不是 C 语法。我确定这是一个简单的过程,但我对 Objective 来说还是个新手 - c 我需要它来完成一个可可项目。此代码将日历输出为一系列连续的字符串,直到最后一个月。soo 我如何输入日历而不是在终端中创建日历,一系列 NSMatrixes 取决于输入的年份。
希望有人能帮助我,谢谢或一切帮助(你是完成程序的功劳):)(日历只是我制作的程序的一小部分,它是重要的部分之一!!)