cocoa - How do I make an NSView move to the front of all NSViews

Question

I have a super view, which has 2 subviews. These subviews are overlapped.

Whenever i choose a view from a menu, corresponding view should become the front view and handle actions. i.e., it should be the front most subview.

acceptsFirstResponder resigns all work fine. But the mouse down events are sent to the topmost sub view which was set.

Regards, Dhana

Answer 1

Here's another way to accomplish this that's a bit more clear and succinct:

[viewToBeMadeForemost removeFromSuperview];
[self addSubview:viewToBeMadeForemost positioned:NSWindowAbove relativeTo:nil];

Per the documentation for this method, when you use relativeTo:nil the view is added above (or below, with NSWindowBelow) all of its siblings.

Answer 2

Another way is to use NSView's sortSubviewsUsingFunction:context: method to re-order a collection of sibling views to your liking. For example, define your comparison function:

static NSComparisonResult myCustomViewAboveSiblingViewsComparator( NSView * view1, NSView * view2, void * context )
{    
    if ([view1 isKindOfClass:[MyCustomView class]])    
        return NSOrderedDescending;    
    else if ([view2 isKindOfClass:[MyCustomView class]])    
        return NSOrderedAscending;    

    return NSOrderedSame;
}

Then when you want to ensure your custom view remains above all sibling views, send this message to your custom view's superview:

[[myCustomView superview] sortSubviewsUsingFunction:myCustomViewAboveSiblingViewsComparator context:NULL];

Alternatively, you can move this code to the superview itself, and send the message sortSubviewsUsingFunction:context: to self instead.

Answer 3

using @Dalmazio's answer in a Swift 4 category that mimics the equivalent UIView method gives the following:

extension NSView {

    func bringSubviewToFront(_ view: NSView) {
            var theView = view
            self.sortSubviews({(viewA,viewB,rawPointer) in
                let view = rawPointer?.load(as: NSView.self)

                switch view {
                case viewA:
                    return ComparisonResult.orderedDescending
                case viewB:
                    return ComparisonResult.orderedAscending
                default:
                    return ComparisonResult.orderedSame
                }
            }, context: &theView)
    }

}

so, to bring subView to the front in containerView

containerView.bringSubviewToFront(subView)

unlike solutions which remove and re-add the view, this keeps constraints unchanged

Answer 4

I was able to get this to work without calling removeFromSuperView

// pop to top
[self addSubview:viewToBeMadeForemost positioned:NSWindowAbove relativeTo:nil];

Answer 5

You can achieve this by just adding the view again; it will not create another instance of it.

[self addSubview:viewToBeMadeForemost];

You can Log the number of subviews before and after this line of code is executed.

Answer 6

Below given code should work fine..

    NSMutableArray *subvies = [NSMutableArray arrayWithArray:[self subviews]];//Get all subviews..

    [viewToBeMadeForemost retain]; //Retain the view to be made top view..

    [subvies removeObject:viewToBeMadeForemost];//remove it from array

    [subvies addObject:viewToBeMadeForemost];//add as last item

    [self setSubviews:subvies];//set the new array..

Answer 7

You might try this:

[viewToBeMadeFirst.window makeKeyAndOrderFront:nil];