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我shell_exec在以下变量上使用函数在 shell 上执行命令：

  1. fname（仅限字符）
  2. fpack（仅限字符）
  3. email（有效的电子邮件地址）

我的代码是：

<?php

require_once 'connectionToDB.php';

$fname = mysqli_real_escape_string($dbc, filter_var(escapeshellarg($_POST['fname']), FILTER_SANITIZE_STRING));
$fpack = mysqli_real_escape_string($dbc, filter_var(escapeshellarg($_POST['fpack']), FILTER_SANITIZE_STRING));
$email = mysqli_real_escape_string($dbc, filter_var(escapeshellarg($_POST['email']), FILTER_SANITIZE_EMAIL));

/** Verify name of applicaion **/
if(!ctype($fname)) {
    $op = json_encode(array('type' => 'error', 'msg' => 'Application name must be in english alphabetical letters only'));
    die($op);
}
if(strlen($fname)>20) {
    $op = json_encode(array('type' => 'error', 'msg' => 'Application name must be less than 20 characters'));
    die($op);
}

/** Verify name of package **/
if(!ctype($fpack)) {
    $op = json_encode(array('type' => 'error', 'msg' => 'Package name must be in english alphabetical letters only'));
    die($op);
}
if(strlen($fpack)>20) {
    $op = json_encode(array('type' => 'error', 'msg' => 'Package name must be less than 20 characters'));
    die($op);
}

/** Verify user's email **/
if (strlen($email)>50) {
    $op = json_encode(array('type' => 'error', 'msg' => 'Email must be of less than 50 characters'));
    die($op);
}

if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
    $op = json_encode(array('type' => 'error', 'msg' => 'Please provide a valid email address.'));
    die($op);
}

正如我所说我shell_exec在这些变量上使用，我害怕远程代码执行。我的代码是否足够安全以防止 RCE？

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