我前段时间遇到了这个问题,我像你一样解决了它,但后来我意识到我用那个解决方案我不能使用 i18n,因为字符串是在枚举类中硬编码的。所以我修改了我的 enumConverter 以messages
用于渲染。
此外,有时您可能希望将枚举呈现为某个唯一标识符,而不是用户可读的文本(供某些组件内部使用)。
这是我的转换器:
import java.util.ResourceBundle;
/*
* Licensed to the Apache Software Foundation (ASF) under one
* or more contributor license agreements. See the NOTICE file
* distributed with this work for additional information
* regarding copyright ownership. The ASF licenses this file
* to you under the Apache License, Version 2.0 (the
* "License"); you may not use this file except in compliance
* with the License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing,
* software distributed under the License is distributed on an
* "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
* KIND, either express or implied. See the License for the
* specific language governing permissions and limitations
* under the License.
*/
import javax.faces.component.UIComponent;
import javax.faces.component.UIInput;
import javax.faces.context.FacesContext;
import javax.faces.convert.Converter;
import javax.faces.convert.ConverterException;
import com.eyeprevent.configuration.ConfigurationReader;
/**
* converts an enum in a way that makes the conversion reversible (sometimes)
* <ul>
* <li>input: uses its classname and ordinal, reversible<li>
* <li>else: uses its name, non reversible<li>
* </ul>
*/
public class EnumConverter implements Converter
{
@SuppressWarnings("unchecked")
public Object getAsObject(FacesContext context, UIComponent component, String value) throws ConverterException
{
if (value == null || value.length() < 1)
{
return null;
}
int pos = value.indexOf('@');
if (pos < 0)
{
throw new IllegalArgumentException(value + " do not point to an enum");
}
String className = value.substring(0, pos);
Class clazz;
int ordinal = Integer.parseInt(value.substring(pos+1), 10);
try
{
clazz = Class.forName( className, true, Thread.currentThread().getContextClassLoader() );
// if the clazz is not an enum it might be an enum which is inherited. In this case try to find the superclass.
while (clazz != null && !clazz.isEnum())
{
clazz = clazz.getSuperclass();
}
if (clazz == null)
{
throw new IllegalArgumentException("class " + className + " couldn't be treated as enum");
}
Enum[] enums = (Enum[]) clazz.getEnumConstants();
if (enums.length >= ordinal)
{
return enums[ordinal];
}
}
catch (ClassNotFoundException e1)
{
throw new RuntimeException(e1);
}
throw new IllegalArgumentException("ordinal " + ordinal + " not found in enum " + clazz);
}
public String getAsString(FacesContext context, UIComponent component, Object value) throws ConverterException
{
if (value == null)
{
return "";
}
Enum<?> e = (Enum<?>) value;
if (component instanceof UIInput || UIInput.COMPONENT_FAMILY.equals(component.getFamily()))
{
return e.getClass().getName() + "@" + Integer.toString(e.ordinal(), 10);
}
ResourceBundle messages =ConfigurationReader.getMessages(context.getViewRoot().getLocale());
return messages.getString(e.name());
}
}