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我正在使用以下顶点着色器（由http://stemkoski.github.io/Three.js/Shader-Heightmap-Textures.html提供）从灰度高度图生成地形：

uniform sampler2D bumpTexture;
uniform float bumpScale;

varying float vAmount;
varying vec2 vUV;

void main()
{
  vUV = uv;
  vec4 bumpData = texture2D( bumpTexture, uv );

  vAmount = bumpData.r; // assuming map is grayscale it doesn't matter if you use r, g, or b.

  // move the position along the normal
  vec3 newPosition = position + normal * bumpScale * vAmount;

  gl_Position = projectionMatrix * modelViewMatrix * vec4( newPosition, 1.0);
}

我想要 32 位的分辨率，并生成了一个将高度编码为 RGBA 的高度图。我不知道如何更改着色器代码以适应这种情况。任何方向或帮助？

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2 回答 2

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bumpData.r, .g,.b和.a都是 [0.0, 1.0] 范围内的量，等于原始字节值除以255.0.

因此，根据您的字节顺序，返回原始 int 的天真转换可能是：

(bumpData.r * 255.0) + 
(bumpdata.g * 255.0 * 256.0) + 
(bumpData.b * 255.0 * 256.0 * 256.0) + 
(bumpData.a * 255.0 * 256.0 * 256.0 * 256.0)

所以这与向量的点积相同(255.0, 65280.0, 16711680.0, 4278190080.0)，这可能是实现它的更有效的方法。

于 2015-02-21T23:42:33.377 回答
0

用三个js

const generateHeightTexture = (width) => {
  // let max_texture_width = RENDERER.capabilities.maxTextureSize;
  let pixels = new Float32Array(width * width)
  pixels.fill(0, 0, pixels.length);
  let texture = new THREE.DataTexture(pixels, width, width, THREE.AlphaFormat, THREE.FloatType);

  texture.magFilter = THREE.LinearFilter;
  texture.minFilter = THREE.NearestFilter;
  // texture.anisotropy = RENDERER.capabilities.getMaxAnisotropy();
  texture.needsUpdate = true;
  console.log('Built Physical Texture:', width, 'x', width)
  return texture;
}
于 2018-11-02T01:38:57.797 回答