4

我不太确定这里的术语,所以请多多包涵……

假设我有一个这样的构造函数调用:

machineSpecificEnvironment = Environment(
   TI_C28_ROOT = 'C:/appl/ti/ccs/4.1.1/ccsv4/tools/compiler/c2000',
   JSDB = 'c:/bin/jsdb/jsdb.exe',
   PYTHON_PATH = 'c:/appl/python/2.6.4',
)

除了我想通过对提供给我的字典的操作来替换它:

keys = {'TI_C28_ROOT': 'C:/appl/ti/ccs/4.1.1/ccsv4/tools/compiler/c2000',
        'JSDB': 'c:/bin/jsdb/jsdb.exe',
        'PYTHON_PATH': 'c:/appl/python/2.6.4'}
machineSpecificEnvironment = Environment(
     ... what do I put here? it needs to be a function of "keys" ...
)

我怎样才能做到这一点?

4

2 回答 2

5
machineSpecificEnvironment = Environment(**keys)
于 2010-05-18T14:20:21.873 回答
3

您可以通过 ** 表示法将 dict 用作​​参数列表

machineSpecificEnvironment = Environment(**keys)
于 2010-05-18T14:21:21.233 回答