1

我是一个初学者,但我已经设法为我的网站整理了一份反馈表。我遇到的问题是表单发送了 2 封电子邮件而不是 1 封。关于导致此问题的任何想法?

$('#myForm') 
    .on('valid.fndtn.abide', function () {
    var name = $("input#name").val();
    var email = $("input#email").val();
    var message = $("textarea#message").val();

    var dataString = 'name=' + name +
          '&email=' + email +
          '&message=' + message;

    $.ajax({
      type: "POST",
      url: "/contact/mail.php",
      data: dataString,
      success: function() {
        $('.contactform').html("<div id='thanks'></div>");
          $('#thanks').html("<h2>Thanks!</h2>")
          .append("<p>Dear "+ name +"!, We will get back to you as soon as we can.</p>")
          .hide()
          .fadeIn(1500);
      },
    });  //ajax call
    return false;
 });

PHP:

<?php

$name = $_POST["name"];
$email = $_POST["email"];
$message = $_POST["message"];

$msg = "

Name: $name
Email: $email
Comments:
$message
";

$to = "email@example.com";
$subject = "Website";
$message = $msg;
$headers = "Website";
mail($to,$subject,$message,$headers);

?>
4

1 回答 1

0

显然,Foundation 5 仍然包含来自先前版本“valid”与“valid.fndtn.abide”的旧调用函数,这导致它被调用两次。通过进行以下更改,我能够防止重复发送电子邮件:

$('#myForm') 
.on('valid.fndtn.abide', function (e) {
  if(e.namespace != 'abide.fndtn') {
    return;
  }
  var name = $("input#name").val();
  var email = $("input#email").val();
  var message = $("textarea#message").val();
于 2015-02-18T04:09:43.480 回答