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我有存储过程：

USE [Auth]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
----------------------------------------------------------------------------------------------------------------------------------------
ALTER Procedure [dbo].[User_InfoByLogin]
@login nvarchar(10)
AS
begin

declare @id_client numeric(18,0)
declare @id_session numeric(18,0)

select @id_client=id from auth_Clients where [login]=@login

if @id_client is null
begin
    select -1 err, 'Пользователь не найден' err_msg,'' err_sys_msg
    return
end


select 0 err, 'Успешное получение данных' err_msg,'' err_sys_msg

select
cl.[login] as login,
cl.email,
cl.active,
convert(varchar, cl.date_reg, 104) as date_reg,
cl.space,
cl.id_ext,
cl.blocked,
cl.stopped,
convert(varchar, cl.stopped_date, 104) as stopped_date,
fz.name_First,
fz.name_Last,
fz.name_Father,
tf.limit_device,
tf.limit_cam,
tf.limit_video,
ct.id_tax as tarif
from 
auth_Clients cl
join auth_ClientsFz fz on cl.id=fz.id_client
LEFT JOIN auth_ClientTaxes AS ct ON cl.id=ct.id_client
LEFT JOIN auth_Tarifs AS tf ON ct.id_tax=tf.id
where 
fz.id_client=@id_client

end

以及一些执行此存储过程的 php 代码：

public static function GetUserInfo($procName, $params){
    $conf = new Config();
    $conf->Init();
    if ($conf){ 
        $callProc = "exec $procName 
        @login = '$params[login]'
        ";              
        $user_info = $conf->db->get_results($callProc);
        echo 'OK';
        $conf->db->vardump($user_info);
    }
    else{
        echo 'Ошибка подключения к базе данных';
    }
}

我得到的只是第一次选择的结果：

OK ezSQL (v2.17) 变量转储..

数组 ( [0] => stdClass 对象 ( [err] => 0 [err_msg] => Успешное получение данных [err_sys_msg] => )

)

类型：数组 最后查询 [1]：exec User_InfoByLogin @login = '9193390677' 最后函数调用：$db->query("exec User_InfoByLogin @login = '9193390677'") 最后返回的行数：1

我正在使用 ezsql 连接到 db 并使用它：

//данные для подключения к бд
    public $db_name = '******';
    public $db_host = '******';
    public $db_user = '******';
    public $db_pass = '******';
    //база данных для ez sql
    public $db;

    public function Init(){
        $this->db = new ezSQL_mssql($this->db_user, $this->db_pass, $this->db_name, $this->db_host);
    }

是否有任何选项可以从第二个选择中获取结果，例如将它们合并到一个选择语句中？

4

0 回答 0