使用Microsoft COBOL 编译器 2.2 版,我的代码完全可以正常工作。
IDENTIFICATION DIVISION.
PROGRAM-ID. COCENTRY.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT COC-FILE
ASSIGN TO DISK
ORGANIZATION IS INDEXED
ACCESS MODE IS RANDOM
RECORD KEY IS COCNO
FILE STATUS IS FILE-STATUS.
DATA DIVISION.
FILE SECTION.
FD COC-FILE LABEL RECORD IS STANDARD
VALUE OF FILE-ID IS "COC.DAT".
01 COC-RECORD.
03 COCNO PIC 9(5).
03 COCDESC PIC X(40).
WORKING-STORAGE SECTION.
01 FILE-STATUS PIC XX.
01 ESC-CODE PIC 99 VALUE 0.
88 ESC-KEY VALUE 1.
88 F2 VALUE 3.
88 F10 VALUE 11.
01 ERRMSG PIC X(70) VALUE SPACES.
01 ERR PIC 9 VALUE 0.
SCREEN SECTION.
01 FORM1.
03 BLANK SCREEN BACKGROUND-COLOR 1.
03 LINE 1 COLUMN 1 'COCNO'.
03 LINE 2 COLUMN 1 'COCDESC'.
03 LINE 24 COLUMN 1 "Esc=Exit F2=Save F10=Cancel".
03 LINE 25 COLUMN 1 PIC X(70) FROM ERRMSG HIGHLIGHT.
01 FORM2.
03 LINE 1 COLUMN 14 PIC 9(5)
USING COCNO REVERSE-VIDEO.
03 LINE 2 COLUMN 14 PIC X(40)
USING COCDESC REVERSE-VIDEO.
03 LINE 24 COLUMN 1 PIC 99
USING ESC-CODE.
PROCEDURE DIVISION.
MAIN.
OPEN I-O COC-FILE.
IF FILE-STATUS NOT = '00'
OPEN OUTPUT COC-FILE
CLOSE COC-FILE
OPEN I-O COC-FILE.
PERFORM ENTRY1 THRU ENTRYX UNTIL ESC-KEY.
CLOSE COC-FILE.
STOP RUN.
ENTRY1.
MOVE SPACES TO COC-RECORD.
MOVE ZEROES TO COCNO.
ENTRY2.
DISPLAY FORM1 FORM2.
ACCEPT FORM2.
ACCEPT ESC-CODE FROM ESCAPE KEY.
IF F10
MOVE 'Entries canceled...' TO ERRMSG
GO ENTRY1
ELSE IF F2
GO ENTRY3
ELSE IF ESC-KEY
GO ENTRYX
ELSE
GO ENTRY2.
ENTRY3.
MOVE 0 TO ERR.
WRITE COC-RECORD INVALID KEY MOVE 1 TO ERR.
IF ERR = 1
MOVE 'Duplicate key not allowed...' TO ERRMSG
GO ENTRY2
ELSE
MOVE 'Entries recorded...' TO ERRMSG
GO ENTRY1.
ENTRYX.
EXIT.
现在我正在使用具有 GNUCobol 版本 1.1.0 的 OpenCobol IDE 4.3.0,并且我被提示这几行
syntax error, unexpected "Literal", expecting LEADING or TRAILING
03 LINE 1 COLUMN 1 'COCNO'.
03 LINE 2 COLUMN 1 'COCDESC'.
03 LINE 24 COLUMN 1 "Esc=Exit F2=Save F10=Cancel".
所以我通过添加VALUE关键字来修复它们:
03 LINE 1 COLUMN 1 VALUE 'COCNO'.
03 LINE 2 COLUMN 1 VALUE 'COCDESC'.
03 LINE 24 COLUMN 1 VALUE "Esc=Exit F2=Save F10=Cancel".
但是一旦我这样做,我就会得到另一个提示
'ACCEPT .. FROM ESCAPE KEY' not implemented
在这条线上
ACCEPT ESC-CODE FROM ESCAPE KEY.
这可能是什么原因?什么可以解决这个问题?