10 
com.mongodb.CommandFailureException: { "serverUsed" : "localhost:27017" , "createdCollectionAutomatically" : true , "numIndexesBefore" : 1 , "ok" : 0.0 , "errmsg" : "namespace name generated from index name \"NDS.ABCD_pre_import.$importabilityEvaluations.perNameResults.straightImportResults.resultPolContent_NOT_IN_CURRENT_USE.officialPolResultNameContentId\" is too long (127 byte max)" , "code" : 67}
    at com.mongodb.CommandResult.getException(CommandResult.java:76)
    at com.mongodb.CommandResult.throwOnError(CommandResult.java:131)
    at com.mongodb.DBCollectionImpl.createIndex(DBCollectionImpl.java:362)
    at com.mongodb.DBCollection.createIndex(DBCollection.java:563)
    at org.springframework.data.mongodb.core.index.MongoPersistentEntityIndexCreator.createIndex(MongoPersistentEntityIndexCreator.java:136)
    at org.springframework.data.mongodb.core.index.MongoPersistentEntityIndexCreator.checkForAndCreateIndexes(MongoPersistentEntityIndexCreator.java:129)
    at org.springframework.data.mongodb.core.index.MongoPersistentEntityIndexCreator.checkForIndexes(MongoPersistentEntityIndexCreator.java:121)
    at org.springframework.data.mongodb.core.index.MongoPersistentEntityIndexCreator.onApplicationEvent(MongoPersistentEntityIndexCreator.java:105)
    at org.springframework.data.mongodb.core.index.MongoMappingEventPublisher.publishEvent(MongoMappingEventPublisher.java:60)
    at org.springframework.data.mapping.context.AbstractMappingContext.addPersistentEntity(AbstractMappingContext.java:306)
    at org.springframework.data.mapping.context.AbstractMappingContext.getPersistentEntity(AbstractMappingContext.java:180)
    at org.springframework.data.mapping.context.AbstractMappingContext.getPersistentEntity(AbstractMappingContext.java:140)
    at org.springframework.data.mapping.context.AbstractMappingContext.getPersistentEntity(AbstractMappingContext.java:67)
    at org.springframework.data.mongodb.core.MongoTemplate.determineCollectionName(MongoTemplate.java:1881)
    at org.springframework.data.mongodb.core.MongoTemplate.determineEntityCollectionName(MongoTemplate.java:1868)
    at org.springframework.data.mongodb.core.MongoTemplate.save(MongoTemplate.java:825)
4

3 回答 3

26

您可以将索引名称作为参数传递给 ensureIndex：

db.collection.ensureIndex({"birds.parrots.macaw.blue.id": 1}, {name:"myIndex1"});

db.collection.ensureIndex({"birds.parrots.macaw.blue.id": 1, "field2": 1}, {name:"myIndex1"});
于 2015-10-18T19:02:30.927 回答
0

记录我的情况以供其他参考：

  • 我的情况：代码
        indexKeyList = [
            ("shortLink", pymongo.ASCENDING),
            ("parsedLink.isParseOk", pymongo.ASCENDING),
            ("parsedLink.errType", pymongo.ASCENDING),
            ("parsedGame.realGameName", pymongo.ASCENDING),
            ("parsedGame.gameTheme", pymongo.ASCENDING),
        ]
        mongoCollectionShortlink.create_index(indexKeyList)
  • 报告错误：
发生异常: OperationFailure

namespace name generated from index name "shortLink.gameShortLink.$shortLink_1_parsedLink.isParseOk_1_parsedLink.errType_1_parsedGame.realGameName_1_parsedGame.gameTheme_1" is too long (127 byte max), full error: {'ok': 0.0, 'errmsg': 'namespace name generated from index name "shortLink.gameShortLink.$shortLink_1_parsedLink.isParseOk_1_parsedLink.errType_1_parsedGame.realGameName_1_parsedGame.gameTheme_1" is too long (127 byte max)', 'code': 67, 'codeName': 'CannotCreateIndex'}

  • 根本原因：使用create_index创建多个索引。然后多个索引名称连接在一起，导致名称太长，超过 127 字节限制

  • 解决方案：应该使用create_indexes

import pymongo
from pymongo import IndexModel

        indexShortLink = IndexModel([("shortLink", pymongo.ASCENDING)], name="shortLink")
        indexIsParseOk = IndexModel([("parsedLink.isParseOk", pymongo.ASCENDING)], name="parsedLink_isParseOk")
        indexErrType = IndexModel([("parsedLink.errType", pymongo.ASCENDING)], name="parsedLink_errType")
        indexRealGameName = IndexModel([("parsedGame.realGameName", pymongo.ASCENDING)], name="parsedGame_realGameName")
        indexGameTheme = IndexModel([("parsedGame.gameTheme", pymongo.ASCENDING)], name="parsedGame_gameTheme")
        indexModelList = [
            indexShortLink,
            indexIsParseOk,
            indexErrType,
            indexRealGameName,
            indexGameTheme,
        ]
        mongoCollectionShortlink.create_indexes(indexModelList)
于 2021-08-19T02:14:17.027 回答
-1

您不能禁用索引，因为 MongoDB 将始终为_id. 改为缩短您的收藏名称 - 也可以为您节省一些输入

于 2015-02-10T22:09:57.613 回答