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我正在为我的操作系统类做一个项目，我们需要创建一个程序来读取 3 位整数的文本文件，解释整数的每个数字以完成指定的任务，然后打印出每个寄存器在执行结束时。

我确信我的代码并不完全有说服力，但我现在遇到的主要问题是每次尝试运行它时，都会收到错误“系统找不到合适的主方法”。没有编译器错误。Java 文件的名称是“Assignment1.java” 任何帮助表示赞赏。

import java.util.Scanner;
import java.io.*;

public class Assignment1
{               
    public static void main(String[] args) throws FileNotFoundException
    {
        try
        {
            int counter = 0;
            int[] registers = new int[10]; // Create an array of integers to represent the instruction registers

                for(int i = 0; i < registers.length; i++) // Initialize each register to 0
                {
                    registers[i] = 0;
                }

            Scanner fileScan = new Scanner(new File("input1.txt"));
            fileScan.useDelimiter(" ");

            while(fileScan.hasNext())
            {
                number = fileScan.nextInt(); // Scan the instruction
                String instr = number.toString(); // Convert the instruction to a String

                if(instr.length()=3 && counter<=1000) // Verify no more than 1000 instructions will be executed and they are 3-digit numbers
                {
                    executeInstr(instr);
                }
            }

            System.out.println("Register 0:   " + registers[0]);
            System.out.println("Register 1:   " + registers[1]);
            System.out.println("Register 2:   " + registers[2]);
            System.out.println("Register 3:   " + registers[3]);
            System.out.println("Register 4:   " + registers[4]);
            System.out.println("Register 5:   " + registers[5]);
            System.out.println("Register 6:   " + registers[6]);
            System.out.println("Register 7:   " + registers[7]);
            System.out.println("Register 8:   " + registers[8]);
            System.out.println("Register 9:   " + registers[9]);
            System.out.println();
            System.out.println("Number of instructions executed:   " + counter);

        }

        catch(FileNotFoundException ex)
        {
            System.out.println("An error has occured. The file cannot be found.");
        }
    }

    public static void executeInstr(String s) // method to implement instructions
            {
                instruction = s;    
                counter++;
                int dig1 = (int)instruction.charAt(0); // convert first digit of the instruction to an integer variable
                int dig2 = (int)instruction.charAt(1); // convert second digit of the instruction to an integer variable
                int dig3 = (int)instruction.charAt(2); // convert third digit of the instruction to an integer variable

                case 1: dig1=1
                    break;
                case 2: dig1=2
                    registers[dig2]=dig3;
                    break;
                case 3: dig1=3
                    registers[dig2]=registers[dig2]+dig3;
                    break;
                case 4: dig1=4
                    registers[dig2]=registers[dig2]*dig3;
                    break;
                case 5: dig1=5
                    registers[dig2]=dig3;
                    break;
                case 6: dig1=6
                    registers[dig2]=dig2+dig3;
                    break;
                case 7: dig1=7
                    registers[dig2]=registers[dig2]*dig3;
                    break;
                case 8: dig1=8
                    break;
                case 9: dig1=9
                    break;
                case 10: dig1=0
                    break;
                default:
                    System.out.println("Invalid entry.");
                    break;
            }
}
4

1 回答 1

1

我看到的一个问题是你已经嵌套public static void executeInstr(String s)在你的 main 方法中。这是禁止的。相反，将您的方法移动到您的Assignment1类中，就像您的主要方法一样。

public class Assignment1 {
  public static void executeInstr(String s) {
    // your method logic here
  }

  public static void main(String[] args) {
    // your main program code here
    executeInstr(myString);
  }
}

这应该为您编译和运行。

于 2015-02-09T01:02:24.757 回答